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R
Raj Pandey

Contributor-Level 9

Functional group isomers

 

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V
Vishal Baghel

Contributor-Level 10

Given the equations:
t? (A + 2B) = -1 which expands to t? (A) + 2t? (B) = -1 . (I)
t? (2A - B) = 3 which expands to 2t? (A) - t? (B) = 3 . (II)

Solving equations (I) and (II) simultaneously, we get:
t? (A) = 1
t? (B) = -1

Therefore, t? (A) - t? (B) = 1 - (-1) = 2.

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

Haematite: Fe? O?

Bauxite: Al? O? ·xH? O

Magnetite: Fe? O?

Malachite: CuCO? ·Cu (OH)?

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R
Raj Pandey

Contributor-Level 9

Matching Calcium Compounds to their Description:

o   Ca (OCl)? : Bleach

o   CaSO? • ½ H? O: Plaster of paris

o   CaO: Component of cement

o   CaCO? : Antacid

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R
Raj Pandey

Contributor-Level 9

Reaction Sequence:

o   NO? + CH? COOH → HNO? + CH? COO?

o   Sulphanilic acid (+ NH? CH? COO? ) + HNO? → N-acetylated diazonium intermediate + 2H? O

The intermediate + another molecule → Red Azodye + NH? + CH? COOH

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A
Aadit Singh Uppal

Contributor-Level 10

Unimolecular Reactions might seem to not participate in the collision theory due to the presence of only a single molecule. In such cases, the molecule is activated by external forces such as heat, light, electricity, or by colliding with the walls of the container. This force charges the molecule enough to break the activation barrier and result in an effective collision.

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2 months ago

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R
Raj Pandey

Contributor-Level 9

Potential difference across resistor at time t = V = 30/3 = 10V
Current, I = 10 / (5 * 10? ) = 2? A

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2 months ago

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A
alok kumar singh

Contributor-Level 10

100 mol of KBr is doped with 10? mol of SrBr?

Therefore, 1 mol of KBr contains 10? mol of SrBr?

Molar mass of KBr = 119 g/mol .

119 g of KBr contains 10? mol of SrBr?

1 g of KBr contains (10? / 119) mol of SrBr?

Each Sr²? ion introduced creates one cation vacancy to maintain electrical neutrality.

Number of cation vacancies = (moles of SrBr? ) * (Avogadro's number)

Number of vacancies = (10? / 119) * (6.023 * 10²³) = 5.06 * 10¹?

The answer provided in the document is "5 (Rounded off)", which likely refers to the coefficient 5.06.

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2 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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A
alok kumar singh

Contributor-Level 10

The reaction is N? O? (g)? 2NO? (g).

Δn_g = (moles of gaseous products) - (moles of gaseous reactants) = 2 - 1 = 1.

The relationship between Kp and Kc is Kp = Kc (RT)^Δn_g.

600.1 = 20.4 * (0.0831 * T)¹

T = 600.1 / (20.4 * 0.0831) = 353.99 K.

The answer, rounded off, is 354 K.

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