Class 12th

$v=\frac{p}{m}\Rightarrow v_p:v_d:v_{\alpha }=1:\frac{1}{2}:\frac{1}{4}=4:2:1$

$F_{mag}=qvB\Rightarrow F_P:F_d:F_{\alpha }=1*4:1*2:2*1=2:1:1$

Please find the below image

[h] = ML²T^-1

[E] = ML²T^-2

[V] = ML²T^-2C^-1

[P] = MLT^-1

I > III > IV > II

${\left[Fe{F}_6\right]}^{3-}\to F{e}^{3+}-3d^5-$ all are unpaired (n = 5)

${\left[Co{\left(N{H}_3\right)}_6\right]}^{3+}\to C{o}^{3+}-3d^6-$ all are paired (n = 0)

${\left[NiC{l}_4\right]}^{2-}\to N{i}^{2+}-3d^8\to \left(n=2\right)$

${\left[Cu{\left(N{H}_3\right)}_4\right]}^{2+}\to C{u}^{++}\to 3d^9\to \left(n=1\right)$

Indium and other semi conducting materials behaves different characteristic of impurities and pure particle at high temperature zone. Hence in metallurgical process it is refined by the zone refining.

Buna-S required nascent oxygen

Butadiene + styrene $\underset{}{\overset{\left[0\right]}{\to }}$ (Buna-S)

Magnetic field on the axis of a circular coil at distance x from centre, B = $\frac{{\mu }_{0}Ni{r}^2}{2{\left(r^2+x^2\right)}^{\raisebox{1ex}{$3$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}}$ $\frac{{}_{}{}^{}}{{{}^{}{}^{}}^{\raisebox{1ex}{$$}\!\left/ \!\raisebox{-1ex}{$$}\right.}}$

$\frac{{\left(r^2+{\left(0.2\right)}^2\right)}^{\raisebox{1ex}{$3$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}}{{\left(r^2+{\left(0.05\right)}^2\right)}^{\raisebox{1ex}{$3$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}}=8$ $\frac{r^2+{\left(0.2\right)}^2}{r^2+{\left(0.05\right)}^2}=4\Rightarrow r^2=0.01\Rightarrow r=0.1m.$

Number of half lives of Y = 3

Number of half lives of X = 6 [As half life of X is half of that of Y].

$\frac{N_1}{2^6}=\frac{N_2}{2^3}\Rightarrow \frac{N_1}{N_2}=8$

Conversion form