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New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

Total number of passenger is the Rajdhani Express = 10 * 20 = 200

So, in the 9 boggies the minimum number of total passengers = 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 = 144

Hence, the minimum number of passenger in one boggie can be (200? 144) = 56

New answer posted

5 months ago

0 Follower 9 Views

P
Payal Gupta

Contributor-Level 10

Let A and B work for m days and C for n days to complete the work. Therefore,

m15+m20+n30=1 . (1)

Out of the total of Rs. 18000, B gets Rs. 6000 more than C.

i.e.,  m20n30=600018000=13 . (2)

On adding Eqs. (1) and (2), we get

m15+2m20=45m=8

New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

Let f (x) = px2 + qx + k, where p, q and k are integers, and p ≠ 0

 f (0) = k = 1

 f (x) = px2 + qx + 1

= px2 +qx + k (Differentiate both sides with respect to x)

 f' (x) = 2px + q

For maxima or minima f' (x) = 0, x = q2p

f (x) attains maximum at x = 1

 q = − 2p

f (1) = p + q + 1 = 3

 1 − p = 3

 p = − 2

 q = 4

 f (x) = −2x2 + 4x + 1

f (10) = − 200 + 40 + 1 = −159

New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

f (x) = x – x2 + 1

g (x) = x2 + b + 3

f (2) g (1) < 0

(a – 4 + 1) (1 + 6 + 3) < 0

(a – 3) (b + 4) < 0

New answer posted

5 months ago

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P
Payal Gupta

Contributor-Level 10

100! has 24 zeroes.

100! + 200! = 100! [1 + 101 * 102 * … * 200]

Which will again give 24 zeroes at the end.

New answer posted

5 months ago

0 Follower 4 Views

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Payal Gupta

Contributor-Level 10

So, cars which have atleast one options

= 8 + 4 + 10 + 12 + 2 + 4 + 6 = 46

Hence, cars with no option = 50 – 46 = 4

New answer posted

5 months ago

0 Follower 2 Views

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Payal Gupta

Contributor-Level 10

Let 2P = 3Q = 4R = 5S = K

Then,  P=K2, Q=K3, R=K4, S=K5

K2+K3+=K4+K5=1540

K=1200

Therefore. R = 300, S = 240

Difference=300 - 240 = 60

New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

Capacity of the tube

π ( 1 ) 2 ( 7 1 ) + 2 3 π ( 1 ) 3 = 2 0 3 π

New answer posted

5 months ago

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P
Payal Gupta

Contributor-Level 10

If D < 0 roots are imaginary.

i.e. q2 – 4pr < 0 q2 < 4pr 

New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

Discriminant = (25)24 (1) (3)=2012=8

So, the roots are real and irrational.

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