Class 12th
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New answer posted
5 months agoContributor-Level 10
Let the distance be x km and speed be y km/hr and t be the time in hours. Then the equation will be x = yt …. (1),
Therefore,
Also,
On solving the above equations, we get speed is km/hr time is 6 hrs, and distance is 200 km.
New answer posted
5 months agoContributor-Level 10
Let the speed of A be x km/hr and speed of B be y km/hr, then:
Also,
On solving both equation (1) & (2) we get x = 11 km/hr and y = 10 km/hr.
New answer posted
5 months agoContributor-Level 10
When S1 runs 1900 metres, S3 would run 1862 metres. Hence, the start given is 38/1900 * 2000 = 40 metres
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