Class 12th

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New answer posted

5 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

I

II

III

2 : 5

3 : 4

4 : 5

 

 

 

Hence new ratio

(27+37+49) (57+47+59)

= 73 : 116

New answer posted

5 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Let the distance be x km and speed be y km/hr and t be the time in hours. Then the equation will be x = yt …. (1),

Therefore,  50y+ [x50]3y/5=t+3..... (2)

Also,  100y+ [x100]3y/5=t+2..... (3)

On solving the above equations, we get speed is 1003 km/hr time is 6 hrs, and distance is 200 km.

New answer posted

5 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Let the speed of A be x km/hr and speed of B be y km/hr, then:

55x=55y12..... (1)

Also,  55x=51y110..... (2)

On solving both equation (1) & (2) we get x = 11 km/hr and y = 10 km/hr.

New answer posted

5 months ago

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P
Payal Gupta

Contributor-Level 10

Volume of smaller cone

=13π (3)2*9=27π

=13π (5)2*15=125π

 Volume of the solid = 125π – 27π = 98 π

New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

Px= (P-0.2) (x+100)= (P+0.3) (x-120)

Solving x=1000

New answer posted

5 months ago

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Payal Gupta

Contributor-Level 10

Total S.P. will be

8* [2.36x]+16100 [x4+1]120=18.88x+4.8x+19.2

= [x8]216=27x

Profit = 23.68x + 19.2 − 27x = 19.2 - 3.32x

New answer posted

5 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

Let there be x litres of wine in the beginning

(x8x)2=81100

 x = 80 litres

New answer posted

5 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

When S1 runs 1900 metres, S3 would run 1862 metres. Hence, the start given is  38/1900 * 2000 = 40 metres

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