Class 12th

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New answer posted

a year ago

0 Follower 33 Views

V
Vishal Baghel

Contributor-Level 10

Work done represents are under

F vs x diagram

w3 > w2 > w1 > w4

New answer posted

a year ago

0 Follower 23 Views

V
Vishal Baghel

Contributor-Level 10

 ∑T→.a→=0

T2a1+T4a2+T8a3+T8a4=0

⇒4a1+2a2+a3+a4=0

New answer posted

a year ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

Moles of Fe3O4 = 4.64*103232=20

Moles of CO = 2.52*10328=90

So limiting reagent = Fe3O4

So moles of Fe formed = 60

Weight of Fe = 60 * 56 = 3360

 

New answer posted

a year ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

geff=g+a

=g+g6

=7g6

T'=2πlgeff

T'=67T

New answer posted

a year ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

 e=−Mdidt

M=edi/dt=ML2T−2A−2

 

New answer posted

a year ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

Steam point (T1) = 100°C = 273 + 100 = 373 K

Ice point (T2) = 0°C = 273 K

η= (1−T2T1)*100= (1−273373)*100=26.81%

New question posted

a year ago

0 Follower

New answer posted

a year ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

Three consecutive integers belong to 98 sets and four consecutive integers belongs to 97 sets.

Þ Number of permutations of b1 b2 b3 b4 = number of permutations when b1 b2 b3 are consecutive + number of permutations when b2, b3, b4 are consecutive – b1 b2 b3 b4 are consecutive = 98 * 97 * 98 * 97 – 97 = 18915

New answer posted

a year ago

0 Follower 14 Views

P
Payal Gupta

Contributor-Level 10

g ∝ r 0 ≤ r ≤ R

g ∝ 1 r 2 r > R

New question posted

a year ago

0 Follower 3 Views

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