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6 months ago

Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Nine

Which one of the following reactions indicates the reducing ability of hydrogen peroxide in basic medium?

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alok kumar singh

Contributor-Level 10

In reducing action, H₂O₂ changes to O₂ because it will oxides but option (A) is in acidic medium, hence answer will be (C).

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6 months ago

Class 12th physics ncert exemplar solutions class 12th chapter two

Sixty four conducting drops each of radius 0.02m and each carrying a charge of $5 μ C$ are combined to form a bigger drop. The ratio of surface density of bigger drop to the smaller drop will be:

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Vishal Baghel

Contributor-Level 10

Since, volume remain constant

$64 * \frac{4}{3} π r^{3} = \frac{4}{3} π R^{3}$

R³ = r³ * 64

R = 4r

$\frac{σ_{b i g g e r}}{σ_{s m a l l d r o p}} = \frac{5 * 64 * 4 π^{2}}{4 π R^{2} * 5} = 64 {(\frac{r}{R})}^{2} = 64 {(\frac{r}{4 r})}^{2} = \frac{64}{16} = 4 : 1$

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6 months ago

Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Six

In isolation of which one of the following metals from their ores, the use of cyanide salt is not commonly involved?

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alok kumar singh

Contributor-Level 10

KCN is used as depressant for ZnS. While Au and Ag, cyanide process (leaching) is used.

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6 months ago

Class 12th physics ncert exemplar solutions class 12th chapter two

A parallel plate capacitor with plate area A and plate separation d = 2m has a capacitance of $4 μ F .$ The new capacitance of the system if half of the space between them is filled with a dielectric material of dielectric constant K = 3 (as shown in figure) will be:

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Vishal Baghel

Contributor-Level 10

$G i v e n \frac{\in_{0} A}{d} = 4 μ F$

$C_{1} = \frac{\in_{0} A * 2}{d} \begin{matrix} = 2 * 4 & = 8 μ F \end{matrix}$

$C_{2} = \frac{k \in_{0} A}{d / 2} = 3 * 2 * 4 = 24 μ F$

$C_{e q} = \frac{C_{1} C_{2}}{C_{1} + C_{2}} = \frac{8 * 24}{8 + 24} = \frac{8 * 24}{32} = 6 μ F$

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6 months ago

Class 12th Physics NCERT Exemplar Solutions Class 12th Chapter Fourteen

An aluminium wire is stretched to make its length, 0.4% larger. The percentage change in resistance is

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Payal Gupta

Contributor-Level 10

Volume = constant

$A l = C$

$A d l + l d A = 0$

$\frac{d l}{l} + \frac{d A}{A} = 0$

$\frac{d R}{R} * 100 = (\frac{d l}{l} - \frac{d A}{A}) * 100$

= 0.4 (0.4)

= 0.8 %

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6 months ago

Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Eight

The electronic configuration of Pt (atomic number 78) is:

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alok kumar singh

Contributor-Level 10

Correct electronic configuration of Pt is ⁷⁸Pt = [Xe]4f¹⁴5d⁹6s¹

It is an exceptional electronic configuration

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6 months ago

Class 12th physics ncert exemplar solutions class 12th chapter two

The change on capacitor of capacitance $15 μ F$ in the figure given below is:

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Vishal Baghel

Contributor-Level 10

$\frac{1}{C_{e q}} = \frac{1}{C_{1}} + \frac{1}{C_{2}} + \frac{1}{C_{3}} = \frac{1}{10} + \frac{1}{15} + \frac{1}{20}$

$\frac{1}{C_{e q}} = \frac{6 + 4 + 3}{60} = \frac{13}{60}$

$L_{e q} = \frac{60}{30} μ F$

$Q = C_{e q} v = \frac{60}{13} * 13 μ C$

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6 months ago

Class 12th Nuclei

The magnetic flux through a coil perpendicular to its plane is varying according to the relation $ϕ = (5 t^{3} + 4 t^{2} + 2 t - 5)$ Weber. If the resistance of the coil is 5 ohm, then the induced current through the coil at t = 2s will be

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Payal Gupta

Contributor-Level 10

$V = \frac{- d ?}{d t} = - (15 t^{2} + 8 t + 2)$

at t = 2 sec, V = (15 * 4 + 8 * 2 + 2)

= 78 V

$I = \frac{V}{R} = \frac{78}{5} = 15.6 A$

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6 months ago

Class 12th physics ncert exemplar solutions class 12th chapter two

A flask contains argon and oxygen in the ratio of 3 : 2 in mass and the mixture is kept at 27°C. The ratio of their average kinetic energy per molecule respectively will be:

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Vishal Baghel

Contributor-Level 10

The average kinetic energy (per molecule)of any (ideal) gas (be it monoatomic like Argon, diatomic like oxygen or polyatomic) is always equal to $\frac{3}{2} K_{B} T .$ If depends only on temperature, and is independent of the nature of the gas. So, Answer is 1 : 1.

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6 months ago

Class 12th Chemistry NCERT Exemplar Solutions Class 12th Chapter Five

Which of the following is a correct statements?

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alok kumar singh

Contributor-Level 10

Due to equal and similar charge particle will repel each other, hence will never precipitate

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