Class 12th

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New answer posted

a year ago

0 Follower 5 Views

P
Pallavi Pathak

Contributor-Level 10

The exact weightage varies from year to year. This chapter comes under a broader category which can be "Magnetism" or "Modern Physics". In NEET exam, the chapter's weightage is low to moderate and there can be 6-7% of questions from this chapter.

New answer posted

a year ago

0 Follower 5 Views

P
Pallavi Pathak

Contributor-Level 10

The chapter is one of the small and easy chapter of class 12 Physics. It includes - properties of magnetic materials, magnetic dipoles, and Earth's magnetic field.

New answer posted

a year ago

0 Follower 1 View

P
Pallavi Pathak

Contributor-Level 10

When the electric charges moves, it creates attraction or repulsion. It creates magnetic forces and fields and called magnetism. The term "magnetism and matter" talks about the way magnetic forces and matter interact.

New answer posted

a year ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

From ampere's circuital law

? B ? . d l ? = μ 0 i e n c

= μ 0 3 + 1 = 4 μ 0

New answer posted

a year ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

The relation between α and β  is given as

β = α 1 - α

β 1 = 20 21 1 - 20 21 = 20

β 2 = 100 101 1 - 100 101 = 100

 

New answer posted

a year ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

F ? = e E 0 j ?

a ? y = e E 0 m j ?

= v 0 i ? + e E 0 t m j ?

v ? = v 0 2 + e E 0 t m 2 = v 0 1 + e E 0 t m 2

λ = λ 0 1 + e E 0 t m 2

New answer posted

a year ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

From Lenz law, current in the square loop will be in anticlockwise sense.

New answer posted

a year ago

0 Follower 15 Views

V
Vishal Baghel

Contributor-Level 10

Direction of  is perpendicular to equipotential surface.

New answer posted

a year ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

For diamagnetic ; χ < 0     a n d     l = χ H

New answer posted

a year ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

At resonance VL = VC

⇒ c o s ? = V R V R 2 + ( V L − V C ) 2 = 1

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