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New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

(i) [43x5]=[yz15]

corresponding

By equating the elements of the matrices, we get,

x= 1

y= 4

z= 3.

(ii) [x+y25+zxy]=[6258]

By equating the corresponding elements of the matrices we get,

x+ y = 6 (I)

5 + Z = 5 z=55z=0

xy = 8

 x =8y →(2)

putting eqn(2) in (1) we get

8y + y = 6.

8 + y2 = 6y

y2 6y + 8 = 0.

y2 - 4y - 2y + 8 = 0

y (y-4) -2 (y-4) = 0

(y-4) (y-2) = 0

 y= 4 0r y = 2.

When y = 4,x= 6-y = 6-4 = and z = 0.

Wheny = 2,x = 6-y = 6-2 = 4 and z = 0.

By equating the corresponding elements of the matrices we get,

x+ y + z = 9 -------(i)

x + z = 7 --------(ii)

y + z = 7 -------(iii)

Subtracting eqn (3) from (1) and (2) from (1) we get,

x + y + z -y - z = 9 - 7 and x

...more

New answer posted

8 months ago

0 Follower 28 Views

V
Vishal Baghel

Contributor-Level 10

(E) (i) aij = 12 |3i+j| such that i = 1, 2, 3 and j = 1, 2, 3, 4 for 3 * 4 matrix

So, a11= 12 . |3.1+1|=12|3+1|=12|3+1|=12|2|=22=1.

a12 = 12|3.1+2|=12|1|=12

a13=12|3.1+3|=12*0=0

a14 = 12|3.1+4|=12|1|=12

a21 = 12|3.2+1|=12|6+1|=12|5|=52

a22 = 12|3.2+2|=12|6+2|=12|4|=42=2

a23 = 12|3.2+3|=12|6+3|=12|3|=32

a24=12|32+4|=12|6+4|=12+4|2|=22=1

a31=12|33+1|=12|0+1|=12|8|=82=4.

a32=12|32+2|=12|9+2|=?72=72

a33=12|33+3|=12|9+3|=+6?2=62=3

a34=12|33+4|=12|9+4|=?|5|2=52.

New answer posted

8 months ago

0 Follower 17 Views

V
Vishal Baghel

Contributor-Level 10

(E) (i) aij(i+j)22 such that i = 1, 2 and j = 1 * 2 for 2 * 2 matrix

Therefore a11 = (1+1)22=222=2 A 2*2 = [a11a12a21a22]

a12 = (1+2)22=322=92

a21 (2+1)22=322=92 [292928]

a22 = (2+2)22=422=162=8

New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

As number of elements of matrix with order m * n

(E) Possible order of matrix with 18 elements are (1 * 18), (2 * 9), (3 * 6), (6 * 3), (9 * 2) and (18 * 1)

Similarly, possible order of matrix with 5 elements are (1 * 5) and (5 * 1)

New answer posted

8 months ago

0 Follower 29 Views

V
Vishal Baghel

Contributor-Level 10

As, number of elements of matrix having order m * n = m.n.

(b) So, (possible) order of matrix with 24 elements are (1 * 24), (2 * 12), (3 * 8), (4 * 6), (6 * 4), (8 * 3), (12 * 2), 24 * 1).

Similarly, possible order of matrix with 13 elements are (1 * 13) and (13 * 1)

New answer posted

8 months ago

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V
Vishal Baghel

Contributor-Level 10

Kindly go through the solution

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8 months ago

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P
Payal Gupta

Contributor-Level 10

71.  (i) - (c); (ii)- (d); (iii)- (b); (iv)- (e)

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8 months ago

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New answer posted

8 months ago

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P
Payal Gupta

Contributor-Level 10

70.  (i) - (b); (ii)- (d); (iii)- (a); (iv)- (e); (v)- (c)

New question posted

8 months ago

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