Electrochemistry

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V
Vishal Baghel

Contributor-Level 10

Vitamin B12 is not water soluble chemical.

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Vishal Baghel

Contributor-Level 10

Fe3O4 + 8H+ + 8e -> 3Fe + 4H2O

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V
Vishal Baghel

Contributor-Level 10

K e q = ( 1 2 * 1 0 1 5 ) 1 / 2 = 2 . 2 4 * 1 0 ? 8

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alok kumar singh

Contributor-Level 10

meqofl2=meqofNa2S2O3=20*0.002*1

2 * mmol of l2 = 0.4

mmol of l2 = 0.2 mmol

mmol of Cu2+ = 0.2 * 2 * 10-3

[ C u 2 + ] = 0 . 4 * 1 0 3 1 0 * 1 0 3 = 0 . 0 4 = 4 * 1 0 2 M

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alok kumar singh

Contributor-Level 10

Eext>1.1V , cell reaction is reversed
i.e. Cu? Cu2+ anode
Zn2++2e-? Zn cathode

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Payal Gupta

Contributor-Level 10

C r 2 O 7 2 + 6 e + 1 4 H + 2 C r 3 + + 7 H 2 O  

Here, 6F electricity is required to reduce 1 mol  C r 2 O 7 2 to Cr3+.

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Payal Gupta

Contributor-Level 10

Using ; ksp = 108 S5

1.1 * 10-23 = 108 S5

S = ( 1 1 0 1 0 8 * 1 0 2 5 ) 1 / 5 M 1 0 5 M  

Specific conductance,

λ m 0 = κ 5 * 1 0 0 0 S m 2 m o l 1                              

= 3 * 10-3 Sm2 mol-1

So; x = 3

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Vishal Baghel

Contributor-Level 10

Given cell constant lA=129m1

Ratio of ppm of two solution of KCl = Ratio of moles of per unit volume.

(ppm)KCl1 (ppm)KCl2=M1M2=74.5149.0=12

12=1000*103

 x = 1000

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alok kumar singh

Contributor-Level 10

Sol. Balmer series lies in the visible region.

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