JEE Main

Dear Srusti,

Achieving a 71.5 percentile in JEE Main 2025 typically corresponds to a rank between approximately 260,000 to 380,000. This estimation is based on previous years' data and may vary depending on the total number of candidates and the exam's difficulty level.

Best regards,

Ankit.

Yes, AAA College of Engineering and Technology offers scholarships to students with a JEE Main score. Students having valid JEE Main score of 50 and above with 60% aggregate in Class 12 are eligible for complete tuition fee waiver. The scholarship is offered only to 10 students.

Dear Kiranpreet,

The Joint Entrance Examination (JEE) Main for 2025 is being conducted in two sessions. Session 1 took place from January 22 to 30, 2025, and Session 2 is scheduled from April 1 to 8, 2025. The registration for Session 2 is currently open until February 25, 2025. You can apply through the official NTA website. The JEE Main serves as a gateway for admissions into undergraduate engineering programs across various esteemed institutions in India. For detailed information on eligibility, syllabus, and exam patterns, please refer to the official website.

I hope this information is helpful to you.

Inverse Trigonometric Functions is considered a moderated weightage topic, 1 question is expected from this chapter directly. However, ITF plays an important role to boost score through usgae of its properties in Calculus unit, which have a better weightage overall. Students must check the NCERT Solutions of Inverse Trigonometric functions to build a strong base. Students can check the NCERT ITF Solutions below;

Class 12 Math ITF Solutions

Cutoff Percentiles for JEE MAINS 2025:

General - 95+

Ews - 84+

OBC - 83+

SC - 65+

ST - 50+

It's advisable to regularly check the official JEE Mains website