Maths Continuity and Differentiability

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New answer posted

a month ago

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J
Jaya Sharma

Contributor-Level 10

Some of the common mistakes that people usually make while using logarithmic differentiation have been mentioned below:

  • Not Multiplying by y: After logarithmic differentiation, it is mandatory to multiply by y to solve for dy/dx?
  • Incorrectly Applying the Chain Rule: Make sure that you have correctly used the chain rule whenever you are differentiating a logarithmic expression.
  • Using Wrong Logarithm: It is always advisable to use the natural logarithm (ln) instead of logarithms with other bases.
  • Ignoring Domain Restrictions: Natural logarithm is only defined for the positive real numbers; therefore, y>0 whenever you apply logarithmic diffe
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New answer posted

a month ago

0 Follower 1 View

J
Jaya Sharma

Contributor-Level 10

Logarithmic differentiation is used in the following cases:

  • Logarithmic differentiation is used with functions that have a variable in both base and exponents. In such a case, standard differentiation rules do not apply directly to such functions. This differentiation converts exponentiation into multiplication.
  • Another area where logarithmic differentiation is used is with a function which is the product of a quotient of multiple terms. 
  • Whenever a function has a complex combination of multiplication, division and exponentiation, logarithmic differentiation is preferred. This differentiation eases the complexity by converting multip
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New answer posted

a month ago

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J
Jaya Sharma

Contributor-Level 10

We use parametric equations for the following reasons:

  • Parametric equations represent all those curves that are otherwise impossible to be represented as a single function. Circles, cycloids, ellipses and spirals are all described using parametric equations.
  • These equations can easily describe motion of objects over time.
  • Parametric equations help in breaking down complex relationships into simpler components. Rather than dealing with single complex equation, one can describe x and y seperately in terms of t parameter.
  • These equations extend to three dimensions easily and naturally, so that one can describe curves and surfaces in 3D space.
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New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

Given

( x ) = { 2 s i n ( π x 2 ) , x < 1 | a x 2 + x + b | , 1 x 1 s i n π x , x > 1

If f (x) is continuous for all x R then it should be continuous at x = 1 & x = -1

At x = -1, L.H.L = R.H.L. Þ 2 = |a + b - 1|

=>a + b – 3 = 0  OR  a + b + 1 = 0 . (i)

=>a + b + 1 = 0 . (ii)

           (i) & (ii), a + b =-1

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