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New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

A = ∫? ² lnx dx = 2ln2 – 1
A' = 4 - 2 (2ln2 – 1) = 6 – 4ln2

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

  ( λ , 2 λ , 3 λ )

c o s θ = 6 4 2 s i n θ = 6 4 2 (where q is the angle between L1 & L2)

A r e a Δ O A B = 1 2 ( O A ) ( O B ) s i n θ

= 1 2 ( 3 ) | λ | ( 1 4 ) 6 4 2 = 6 λ = ± 2

            

New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

dy/dx = (e? – x)? ¹
dx/dy = e? - x
dx/dy + x = e? ⇒ I.F. = e^ (∫dy) = e?
∴ xe? = ∫e? dy + c
xe? = e²? /2 + c
y (0) = 0 ⇒ c = -1/2
∴ x = e? /2 - (1/2)e? ⇒ e? – e? = 2x
e²? – 2xe? - 1 = 0
e? = x ± √ (x² + 1) ⇒ e? = x + √ (x² + 1)
y = ln (x + √ (x² + 1)

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

(6!/ (5!1!) * 2! + (6!/ (4!2!) * 2! + (6!/ (3!)²2!) * 2! = 62

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

First element in 20th group is equal to '20'.

(20, 21, ….upto 39 times)

S u m = 3 9 2 ( 2 * 2 0 + ( 3 9 1 ) * 1 )        

            

New answer posted

2 months ago

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Vishal Baghel

Contributor-Level 10

(k-3)/ (h-2) * (k-0)/ (h-0) = -1
⇒ k (2k – 3) = -2 (h – 2)h
⇒ 2h² + 2k² – 4h – 3k = 0
2x² + 2y² – 4x – 3y = 0
(0,0)

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

(5³)^740 * 5² = 5² (125)^740 = 5² (126 – 1)^740
So remainder = 4.

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

C.V. = (σ/x? ) * 100 ⇒ σ = (C.V. * x? ) / 100
∴ σ? = (50*30)/100 = 15 and σ? = (60*25)/100 = 15 ⇒ σ? - σ? = 0

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

Equation of tangent is (x/a) (1/2) + (y/b) (√3/2) = 1
Equation of auxiliary circle is x² + y² = a²
Homogenising (ii) with (i) and making coefficient of x² + coefficient of y² = 0
⇒ (3a²/4b²) - (7/4) = 0 ⇒ e = 2/√7

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

f' (x) = cosx + sinx − k ≤ 0∀x ∈ R
k ≥ √2

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