Ncert Solutions Chemistry Class 11th
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5.37. What is the effect of temperature on (i) surface tension and (ii) Viscosity?
5.37. What is the effect of temperature on (i) surface tension and (ii) Viscosity?
5.37. (i) Surface tension decreases with increase of temperature.
(ii) Viscosity decreases with increase of temperature.
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8.29. Given the standard electrode potentials,
K+/K = -2.93 V, Ag+/Ag = 0.80 V, Hg2+/Hg = 0.79 V, Mg2+/Mg = -2.37 V,
Cr3+/Cr = -0.74 V. Arrange these metals in increasing order of their reducing power.
8.29. Given the standard electrode potentials,
K+/K = -2.93 V, Ag+/Ag = 0.80 V, Hg2+/Hg = 0.79 V, Mg2+/Mg = -2.37 V,
Cr3+/Cr = -0.74 V. Arrange these metals in increasing order of their reducing power.
Lower the electrode potential, better is the reducing agent. Since the electrode potentials increase in the order: K+/K (-2.93 V), Mg2+/Mg (-2.37 V), Cr3+/Cr (-0.74 V), Hg2+/Hg (0.79 V), Ag+/Ag (0.80 V), therefore, reducing power of metals decreases in the same order, i.e., K, Mg, Cr, Hg, Ag.
Upvote 8.28. Arrange the following metals in the order in which they displace each other from the solution of their salts.
Al, Cu, Fe, Mg and Zn.
8.28. Arrange the following metals in the order in which they displace each other from the solution of their salts.
Al, Cu, Fe, Mg and Zn.
Based on the relative positions of these metals in the activity series, the correct order is Mg, Al, Zn, Fe, Cu.
Upvote 5.36. Define Avogadro law, Dalton’s law, Boyle’s law and Charles’ law.
5.36. Define Avogadro law, Dalton’s law, Boyle’s law and Charles’ law.
5.36. Avogadro law states that equal volumes of all gases under same conditions of temperature and pressure contain equal number of molecules.
Dalton's law of partial pressure states that total pressure exerted by a mixture of non-reacting gases is equal to the sum of partial pressures exerted
Upvote 8.27. Predict the products of electrolysis in each of the following:
(i) An aqueous solution of AgNO3 with silver electrodes.
(ii) An aqueous solution of silver nitrate with platinum electrodes.
(iii) A dilute solution of H2SO4with platinum electrodes.
(iv) An aqueous solution of CuCl2 with platinum electrodes.
8.27. Predict the products of electrolysis in each of the following:
(i) An aqueous solution of AgNO3 with silver electrodes.
(ii) An aqueous solution of silver nitrate with platinum electrodes.
(iii) A dilute solution of H2SO4with platinum electrodes.
(iv) An aqueous solution of CuCl2 with platinum electrodes.
(i) An aqueous solution of AgNO3? with silver electrodes.
At cathode: Silver ions have lower discharge potential than hydrogen ions. Hence, silver ions will be deposited in preference to hydrogen ions.
At anode: Silver anode will dissolve to form silver ions in the solution.
Ag → Ag+ + e−
(
Upvote 8.26. Using the standard electrode potentials given in Table 8.1, predict if the reaction between the following is feasible:
(a) Fe3+(aq) and I-(aq) (b) Ag+ (aq) and Cu(s)
(c) Fe3+(aq) and Cu(s) (d) Ag(s) and Fe3+(aq)
(e) Br2 (aq) and Fe3+ (aq). (Advance)
8.26. Using the standard electrode potentials given in Table 8.1, predict if the reaction between the following is feasible:
(a) Fe3+(aq) and I-(aq) (b) Ag+ (aq) and Cu(s)
(c) Fe3+(aq) and Cu(s) (d) Ag(s) and Fe3+(aq)
(e) Br2 (aq) and Fe3+ (aq). (Advance)
(i) When emf is positive, the reaction is feasible.
Eo? cell = Eo? Fe? −Eo? I2? =0.77−0.54=0.23V
Reaction is feasible.
(ii) Eo? cell? =Eo? Ag? −Eo? Cu? =0.80−0.34=0.46V
Reaction is feasible.
(iii) Eo? cell? =Eo? Fe? −Eo? Cu? =0.77−0.34 =0.43 V
Reaction is feasible.
(iv) Eo? cell? =E
Upvote 5.35. When density of liquid and vapours becomes the same; the clear boundary between liquid and vapours disappears. This temperature is called critical temperature.
Upvote 8.25. In Ostwald’s process for the manufacture of nitric add, the first step involves the oxidation of ammonia gas by oxygen gas to give nitric oxide gas and steam. What is the maximum Weight of nitric oxide that can be obtained starting only with 10.0 g of ammonia and 20.0 g of oxygen?
8.25. In Ostwald’s process for the manufacture of nitric add, the first step involves the oxidation of ammonia gas by oxygen gas to give nitric oxide gas and steam. What is the maximum Weight of nitric oxide that can be obtained starting only with 10.0 g of ammonia and 20.0 g of oxygen?
The balanced equation for the reaction is:
4NH3? (g)+5O2? (g)→4NO (g)+6H2? O (g)
The molar masses of ammonia and oxygen are 17 g/mol and 32 g/mol respectively.
68 g of NH3 will react with O2 = 160 g.
Therefore, 10 g of NH3 will react with O2 = 160/68 x 10 g = 23.6 g
But the amount of O2 which is a
Upvote 5.34. The temperature at which the vapour pressure of a liquid is equal to external pressure is called boiling point of liquid.
Upvote 5.33. Liquids can assume the shape of the container. Explain how?
5.33. Liquids can assume the shape of the container. Explain how?
5.33. Molecules of liquids are held together byattractive intermolecular forces. Liquids havedefinite volume because molecules do notseparate from each other. However, moleculesof liquids can move past one another freely, therefore, liquids can flow, can be poured andcan assume the shape of the
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