Ncert Solutions Chemistry Class 11th

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New answer posted•a year ago
S
a year ago

The average O.N. of S in S2O32- is +2 while in S4O62- it is + 2.5. The O.N. of S in SO42- is +6. Since Br2 is a stronger oxidising agent than I2, it oxidises S of S2O32- to a higher oxidation state of +6 and hence forms SO42- ion. I2, however, being weaker oxidising&nbs

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New answer posted•a year ago
S
a year ago

Substance oxidised

Substance reduced

Oxidising agent

Reducing agent

(a) C6H12O6

AgBr

C6H12O6

(b) HCHO

[Ag (NH3)2]+ 

[Ag (NH3)2]+ 

HCHO

(c) HCHO

Cu2+ 

HCHO

(d) N2H4

H2O2

N2H4

(e) Pb

PbO2

Pb

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New answer posted•a year ago
S
a year ago

5.22. Higher the critical temperature, more easily the gas can be liquefied, i.e., greater are the intermolecular forces of attraction. Hence, CO2 has stronger intermolecular forces than CH4.

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New answer posted•a year ago
New answer posted•a year ago
S
a year ago

5.21. At -273°C, volume of the gas becomes equal to zero, i.e., the gas ceases to exist.

 

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New answer posted•a year ago
S
a year ago

The three examples are:

(i) When excess P4?   (reducing agent) reacts with F2? (oxidizing agent),  PF3?  is produced in which P has +3 oxidation number.
                     &

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New answer posted•a year ago
S
a year ago

5.20. SI unit of pressure, P = Nm-2

SI unit of volume = m3

Si unit of temperature, T = K

SI unit of number of moles, n = mol

Thus, SI unit of pV2T2/n = (Nm-2) (m3)2 (K) 2mol = Nm4K2mol-1

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New answer posted•a year ago
S
a year ago

In AgF2,  oxidation state of Ag is +2 which is very unstable. Therefore, it quickly accepts an electron to form the more stable +1 oxidation state.
Ag2+ + e– →Ag+
Therefore, AgF2, if formed, will act as a strong oxidising agent.

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New answer posted•a year ago
S
a year ago

(a) Therefore, it is more appropriate to write the equation for photosynthesis as (iii) because it emphasises that 12H2O are used per molecule of carbohydrate formed and 6H2O are produced during the process.

(b) The purpose of writing O2 two times suggests that O2  is being obtained

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New answer posted•a year ago
S
a year ago

(i) In SO2, O.N. of S is +4. In principle, S can have a minimum O.N. of -2 and maximum of +6. Therefore, S in SO2 can either decrease or increase its O.N. and hence can act both as an oxidising as well as a reducing agent.

(ii) In H2O2, the O.N. of O is -1. In principle, O can have a minimum O

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