Ncert Solutions Chemistry Class 11th

Get insights from 2k questions on Ncert Solutions Chemistry Class 11th, answered by students, alumni, and experts. You may also ask and answer any question you like about Ncert Solutions Chemistry Class 11th

  • 2k

    Questions

  • 0

    Discussions

  • 1

    Active Users

  • 29

    Followers

Have a question about Ncert Solutions Chemistry Class 11th? Ask our experts

Ask Your Question

Keep it short & simple. Type complete word. Avoid abusive language.

New answer posted•a year ago
S
a year ago

(a) Phosphorous, chlorine and sulphur are the non metals which can show disproportionation reaction. The reactions shown are:

P4? + 3OH? + 3H2? O? PH3? + 3H2? PO2?

? Cl2? + 2OH? ? Cl? + ClO? + H2? O

S8? +12OH? ?4S2? +2S2? O32? ? +6H2? O

 

(b) Copper, gallium and indium are the metals that sho

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

The balanced chemical reaction for the redox reaction between chlorine and sulphur dioxide is:

Cl2? + SO2? + 2H2? O → 2Cl− + SO42− ? + 4H+.

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
S
a year ago

(a) F. Fluorine being the most electronegative element shows only a -ve oxidation state of -1.

(b) Cs. Alkali metals because of the presence of a single electron in the valence shell, exhibit an oxidation state of +1.

(c) I. Because of the presence of seven electrons in the valence shell, I shows a

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

The unbalanced chemical reaction is:
Mn3+ (aq) → Mn2+ (aq) + MnO2? (s) + H+ (aq)
The oxidation half reaction is,  
Mn3+ (aq) → MnO2? (s).
To balance oxidation number, one electron is added on R.H.S.
Mn3+ (aq) → MnO2? (s) + e−
4 protons are added to balance the charge.
Mn3+ (aq) → MnO2? (s) + 4H+ (aq)

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

Let x be the O.N. of C.
O.N. of C in cyanogen, (CN)2 = 2 (x – 3) = 0 or x = +3

O.N. of C in cyanide ion, CN- = x – 3 = -1 or x = +2

O.N. of C in cyanate ion, CNO =x-3-2 = -l or x: = +4

The four information about the reaction are:
(i) The reaction involves decomposition of cyanogen, (CN)2 in th

...Read more

Thumbs Up IconUpvote Thumbs Down Icon