Ncert Solutions Chemistry Class 11th
Get insights from 2k questions on Ncert Solutions Chemistry Class 11th, answered by students, alumni, and experts. You may also ask and answer any question you like about Ncert Solutions Chemistry Class 11th
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
10 months agoContributor-Level 10
This is a Long answer type question as classified in NCERT Exemplar
We can Measure the electrode potential of the given species by connecting the redox couple of the given species with standard hydrogen electrode. If it is positive, the electrode of the given species acts as reductant and if it is negative, it acts as an oxidant. Find the electrode potentials of the other given species in the same way, compare the values and determine their comparative strength as an reductant or oxidant. Example Measurement of standard electrode potential of electrode E? Zn2+/Zn using SHE as a reference electrode.
Types of Redox Reactions
The diffe
New answer posted
10 months agoContributor-Level 10
This is a Long answer type question as classified in NCERT Exemplar
We can calculate the oxidation states by - ]
NaClO4 Oxidation no. of chlorine = +7
Suppose oxidation number of chlorine is x then, 1 + x + 4 * (−2) = 0
∴ x - 7 = 0
x = +7
We can calculate, the oxidation states, as given below-
NaClO3 Oxidation no. of chlorine = +5
? NaClO Oxidation no. of chlorine = +1
? KClO2 Oxidation no. of chlorine = +3
? Cl2O7 Oxidation no. of chlorine = +7
ClO3 Oxidation no. of chlorine = +6
Cl2O Oxidation no. of chlorine = +1
NaCl Oxidation no. of chlor
New answer posted
10 months ago
Contributor-Level 10
This is a Long answer type question as classified in NCERT Exemplar
Redox couple are given as
Cu2+/Cu and Zn2+/Zn
Mg2+/Mg and Fe2+ /Fe
Br2/Br- and Cl2 / Cl-
Fe2+ /Fe and Cd2+/Cd
New answer posted
10 months agoContributor-Level 10
This is a Long answer type question as classified in NCERT Exemplar
Disproportionate is defined as the reaction in which one compound of intermediate oxidation state converts to two compounds, one of higher and one of lower oxidation states So, to occur such type of redox reaction, the element should exist in at least three oxidation states. So that element present in the intermediate state and it can change to both higher and lower oxidation state during disproportionate reaction. Fluorine is the most electronegative element and a strong oxidizing agent and is the smallest in size of all the halogens. It does not show a positive oxidat
New answer posted
10 months agoContributor-Level 10
This is a Long answer type question as classified in NCERT Exemplar
On the basis of standard reduction potential suggested in the reactivity series (ii) reaction can take place as Mg has more negative value of E? cell. Hence, Mg will be oxidized by losing electron and iron will be reduced by gaining electron.
New answer posted
10 months agoContributor-Level 10
This is a Long answer type question as classified in NCERT Exemplar
The given reaction is a redox change.
2Na (s)+H2 (g)→2NaH (s)
The half reaction is:
2Na (s)→2Na+ (g)+2e-
The other half reaction is:
H2 (g)+2e-→2H- (g)
This splitting of the reaction into two half-reactions automatically reveals here that sodium is oxidized, and hydrogen is reduced. Any substance which loses electron is oxidized and gains electron is reduced hence is the case of sodium and hydrogen atoms respectively. Hence, the complete reaction is a redox change.
New answer posted
10 months agoContributor-Level 10
(i) Due to inert pair effect Pb2+ is more stable than Pb4+. Whereas Sn4+ is more stable than Sn2+.
(ii) 3Ga+ —–> 2Ga + Ga3+
This is because Ga3+ is more stable than Ga+
New answer posted
10 months agoContributor-Level 10
| Fullerenes are the allotropes of carbon. Its structure is like a soccer ball. They are prepared by heating graphite in electric arc in presence of inert gases such as helium or argon. |
New answer posted
10 months agoContributor-Level 10
The molecules of CO2 are held together by weak van der Waals forces of attraction which can be easily overcome by collisions of the molecules at room temperature. Consequently, CO2 is a gas.
On the other hand, silicon atom forms four single covalent bonds with O-atom which are tetrahedrally arranged and form a three-dimensional structure. Thus, SiO2 is a high melting solid.
New answer posted
10 months agoContributor-Level 10
Carbon dioxide can be obtained as a solid in the form of dry ice by allowing the liquified CO2 to expand rapidly.
Unlike ordinary ice it does not melt and hence does not wet the surface on which it is kept. Thus, it is called dry ice.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 66k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers