Ncert Solutions Chemistry Class 11th

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New answer posted•a year ago
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a year ago

3.45.  (b) It has only ones-electron and hence can be placed in group 1 (alkali metals). It can also gain an electron to achieve a noble gas arrangement and hence it can behave similarly to a group 17 (halogen family) element. Because it is a special case, we shall place hydrogen separately at

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New answer posted•a year ago
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a year ago

The basic skeleton structure of 2-methylbutane is

Placing double bonds at different positions and satisfying the tetra covalency of each carbon, the structures of various alkenes which give 2-methylbutane on hydrogenation are: 

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New question posted•a year ago
New answer posted•a year ago
S
a year ago

Benzene is a rich source of electrons because of the presence of an electron cloud containing 6 n-electrons above and below the plane of the ring. Consequently, it attracts the electrophiles (electron-deficient) reagents towards it and repels nucleophiles (electron- rich) reagents. As a result, benz

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New answer posted•a year ago
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a year ago

3.44.  (d) Assertion is a wrong statement. Non-metallic elements have a strong tendency to gain electrons. Therefore, electronegativity is directly related to those non-metallic properties of elements. It can be further extended to say that the electronegativity is inversely related to the meta

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New answer posted•a year ago
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a year ago

The hybridization state of carbon in these three compounds is:

Since s-electrons are closer to the nucleus, therefore, as the s-character of the orbital making the C—H bond increases, the electrons of C—H bond lie closer and closer to the carbon atom. In other words, the partial +ve charge on the H-a

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New answer posted•a year ago
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a year ago

o-Xylene may be regarded as a resonance hybrid of the following two Kekule structures. Ozonolysis of each one of these gives two products as shown below:

Thus, in all, three products are formed. Since all the three products cannot be obtained from any one of the two Kekule structures, this shows that

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New answer posted•a year ago
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a year ago

Addition of HBr to propene is an ionic electrophilic addition reaction in which the electrophile, i.e., H+ first adds to give a more stable 2° carbocation. In the 2nd step, the carbocation is rapidly attacked by the nucleophile Br~ ion to give 2-bromopropane.

In presence of benzoyl peroxide, the

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New answer posted•a year ago
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a year ago

Branching of carbon atom chain decreases the boiling point of alkane.

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New question posted•a year ago