Ncert Solutions Chemistry Class 11th

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New answer posted•a year ago
New answer posted•a year ago
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a year ago

3.42. (a) Elements of the same group have similar valence shell electronic configuration and, therefore, exhibit similar chemical properties. However, the elements of the same period have an incrementally increasing number of electrons from left to right, and, therefore, have different valences.

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New answer posted•a year ago
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a year ago

(i) The two substituents in the benzene ring are present at p-positions. Therefore, the sequence of reactions should be such that first an o, p-directing group, i.e., Br atom should be introduced in the benzene ring and this should be followed by nitration. Thus,

 
(ii) Here since the two

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New question posted•a year ago
New answer posted•a year ago
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a year ago

 

Due to the presence of a sp3-hybridized carbon, the system is not
planar. It does contain six n-electrons but the system is not fully conjugated since all the six n-electrons do not form a single cyclic electron cloud which surrounds all the atoms of the ring. Therefore, it is not an aromatic c

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New question posted•a year ago
New answer posted•a year ago
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a year ago

The necessary conditions for a molecule to be aromatic are:

  • It should have a single cyclic cloud of delocalised n-electrons above and below the plane of the molecule.
  • It should be planar. This is because complete delocalization of n-electrons is possible only if the ring is planar to allow cyclic over

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New answer posted•a year ago
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a year ago

Benzene is a resonance hybrid of two canonical forms. In the resonance hybrid, all the six pi electrons are completely delocalized. This results in resonance stabilization.

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New answer posted•a year ago
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a year ago

The structures of cis- and trans-isomer of hex-2-ene are:

The boiling point of a molecule depends upon dipole-dipole interactions. Since cis-isomer has higher dipole moment, therefore, it has higher boiling point.

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New answer posted•a year ago
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a year ago

3.40. Within a period, the oxidising character increases from left to right. Therefore, among F, O and N, oxidising power decreases in the order: F > O > N. However, within a group, oxidising power decreases from top to bottom. Thus, F is a stronger oxidising agent than Cl. Further because O is

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