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Ncert Solutions Chemistry Class 11th

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11 months ago

Ncert Solutions Chemistry Class 11th Hydrocarbons

13.8. Write chemical equations for the combustion reaction of the following hydrocarbons:

(i) Butane (ii) Pentene

(iii) Hexyne (iv) Toluene

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Vishal Baghel

Contributor-Level 10

A combustion reaction is a reaction in which a substance reacts with oxygen gas, there is a formation of carbon dioxide, water with the evolution of light and heat.

(i) 2C₄H₁₀ (g) +13 O₂ (g)?8CO₂ (g)+10H₂O (g) + Heat

(ii) 2C₅H₁₀ (g) +15 O₂ (g)?10CO₂ (g)+10H₂O (g) + Heat

(iii) 2C₆H₁₀ (g) +17 O₂ (g)?12CO₂ (g)+10H₂O (g) + Heat

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11 months ago

Ncert Solutions Chemistry Class 11th Hydrocarbons

13.7. Propanal and pentan-3-one are the ozonolysis products of an alkene. What is the structural formula of the alkene?

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Vishal Baghel

Contributor-Level 10

The ozonolysis of 4-Ethylhex-3-ene gives propanal and pentan-3-one.
The structural formula of the alkene (4-Ethylhex-3-ene) is as shown.

(i) Write the structures of propanal and pentan-3-ene with their oxygen atoms facing each other, we have,

(ii) Remove oxygen atoms and join the two fragments by a double bond, the structure of the alkene is

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11 months ago

Ncert Solutions Chemistry Class 11th Classification of Elements and Periodicity in Prop

3.39. Considering the elements B, C, N, F and Si, the correct order of their non-metallic character is:

(a) B>C>Si>N>F

(b) Si>C>B>N>F

(c) F>N>C>B>Si

(d) F>N>C>Si>B

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Payal Gupta

Contributor-Level 10

3.39. In a period, the non-metallic character increases from left to right. Thus, among B, C, N and F, non-metallic character decreases in the order: F > N > C > B. However, within a group, non-metallic character decreases from top to bottom. Thus, C is more non-metallic than Si. Therefore, the correct sequence of decreasing non-metallic character is: F > N > C > B > Si, i.e., option (c) is correct.

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11 months ago

Ncert Solutions Chemistry Class 11th Hydrocarbons

13.6. An alkene 'A' contains three C – C, eight C – H σ bonds and one C – C π bond. 'A' on ozonolysis gives two moles of an aldehyde of molar mass 44 u. Write IUPAC name of 'A'.

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Vishal Baghel

Contributor-Level 10

(i) An aldehyde with molar mass of 44 u is ethanal, CH₃CH=0

(ii) Write two moles of ethanal side by side with their oxygen atoms pointing towards each other.

(iii) Remove the oxygen atoms and join them by a double bond, the structure of alkene 'A' is

As required, but-2-ene has three C—C, eight C—H a? bonds and one C—C? -bond.

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11 months ago

Ncert Solutions Chemistry Class 11th Classification of Elements and Periodicity in Prop

3.38. Considering the elements B, Al, Mg and K, the correct order of their metallic character is:

(a) B>Al>Mg>K

(b) Al>Mg>B>K

(c) Mg>Al>K>B

(d) K>Mg>Al>B

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Payal Gupta

Contributor-Level 10

3.38. In a period, metallic character decreases as we move from left to right. Therefore, metallic character of K, Mg and Al decreases in the order: K > Mg > Al. However, within a group, the metallic character, increases from top to bottom. Thus, Al is more metallic than B. Therefore, the correct sequence of decreasing metallic character is: K > Mg > Al > B, i.e., option (d) is correct

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11 months ago

Ncert Solutions Chemistry Class 11th Hydrocarbons

13.5. An alkene 'A' on ozonolysis gives a mixture of ethanal and pentan-3-one. Write structure and IUPAC name of 'A'.

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Vishal Baghel

Contributor-Level 10

Step 1. Write the structure of the products side by side with their oxygen atoms pointing towards each other.

Step 2. Remove the oxygen atoms and join the two ends by a double bond, the structure of the alkene 'A' is

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11 months ago

Ncert Solutions Chemistry Class 11th Hydrocarbons

13.4. Write IUPAC names of the products obtained by the ozonolysis of the following compounds:
(i) Pent-2-ene (ii) 3, 4-Dimethylhept-3-ene (iii) 2-Ethylbut-l-ene (iv) 1-Phenylbut-l-ene.

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11 months ago

Ncert Solutions Chemistry Class 11th Classification of Elements and Periodicity in Prop

3.37. Which of the following statements is incorrect in relation to ionization enthalpy?

(a) Ionization enthalpy increases for each successive electron.

(b) The greatest increase in ionization enthalpy is experienced on removal of electrons from core noble gas configuration.

(c) End of valence electrons is marked by a big jump in ionization enthalpy.

(d) Removal of electron from orbitals bearing lower n value is easier than from orbital having higher n value.

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Payal Gupta

Contributor-Level 10

3.37. (d) is incorrect.

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11 months ago

Ncert Solutions Chemistry Class 11th Hydrocarbons

13.3. For the following compounds, write structural formulas and IUPAC names for all possible isomers having the number of double or triple bond as indicated:
(a) C₄H₈ (one double bond) (b) C₅H₈ (one triple bond)

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