Ncert Solutions Chemistry Class 11th

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New answer posted•a year ago
S
a year ago

1.22. Speed = Distance / Time

Or, Distance = Speed x Time = 3.0 * 108ms–1 x 2.00 ns = 3.0 * 108ms–1 x 2.00 x 10-9 s = 6 x 10-1 m = 0.600 m

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New answer posted•a year ago
New answer posted•a year ago
S
a year ago

1.20. The values after round up with three significant figures are:

(i) 34.2

(ii) 10.4

(iii) 0.0460

(iv) 2810

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New answer posted•a year ago
S
a year ago

1.19. The significant figures in the given values are:

(i) 2 in 0.0025

(ii) 3 in 208

(iii) 4 in 5005

(iv) 3 in 126,000

(v) 4 in 500.0

(vi) 5 in 2.0034

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New answer posted•a year ago
S
a year ago

1.18. The scientific notation of the given values are:

(i) 4.8*10?3

(ii) 2.34*105

(iii) 8.008*103

(iv) 5.000*102

(v) 6.0012*100

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New answer posted•a year ago
S
a year ago

1.17. 15 ppm means 15 parts per million i.e.15 in 106

So, % by mass = 15/106 x 100 = 15 x 10-4 = 1.5 x 10-3%

Molality = No. of moles of solute/Mass of solvent in kg

Percent by mass = 1.5 x 10-3 % means 100 g of the sample contain 1.5 x 10-3 g chloroform.

So, 1000 g or 1 kg of the sample will conta

...Read more

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New answer posted•a year ago
S
a year ago

1.16. Significant figures are meaningful digits which are known with certainty plus one which is estimated or uncertain. The uncertainty in the experimental or the calculated values is indicated by mentioning the number of significant figures

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

Due to inert pair effect, elements of group 14 exhibit oxidation states of +2 and +4. Thus, option (b) is correct.

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