Ncert Solutions Chemistry Class 11th
Get insights from 2k questions on Ncert Solutions Chemistry Class 11th, answered by students, alumni, and experts. You may also ask and answer any question you like about Ncert Solutions Chemistry Class 11th
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
6 months agoContributor-Level 10
1.39. (d) Taking reference of the ideal gas equation PV= nRT (Where, P= Pressure, V= volume, n=no of moles, R= gas const, T= temperature). It can thus be concluded that volume is directly proportional to the no. of moles.
New question posted
6 months agoNew answer posted
6 months agoContributor-Level 10
1.38 (d) 123.00 has five significant figures. Assertion is wrong statement while reason is a correct statement.
New answer posted
6 months agoContributor-Level 10
All the compounds are crystalline solids and their solubility in water is guided by both lattice enthalpy and hydration enthalpy. In case of sodium and potassium compounds, the magnitude of lattice enthalpy is quite small as compared of sodium and potassium that are mentioned, readily dissolve in water. However, in case of corresponding magnesium and calcium compounds, the cations have smaller sizes and more magnitude of positive charge. This means that their lattice enthalpies are more as compared to the compounds of sodium and potassium. Therefore, the hydroxides and carbonates of these metals are only sparingly soluble in water.
New answer posted
6 months agoContributor-Level 10
This is due to the reason that potassium bicarbonate (KHCO3) formed as an intermediate (when CO2 gas is passed through ammoniated solution of potassium chloride) is highly soluble in water and cannot be separated by filtration.
New answer posted
6 months agoContributor-Level 10
(a) Alkali metals have low ionization enthalpies.
They have a strong tendency to lose 1 electron to form unipositive ions. Thus they show an oxidation state of +1 and are strongly electropositive.
(b) Valence electrons of alkali metals like Na and K easily absorb energy from the
flame and are excited to higher energy levels. When these electrons return to the ground state, the energy is emitted in the form of light.
Magnesium atom has small size so electrons are strongly bound to the nucleus. [ Thus they need large amount of energy for excitation of electrons to higher
energy levels which is not possible in Bunsen flame.
(c)Due to the sma
New answer posted
6 months agoContributor-Level 10
(a) Due to its the lowest ionization energy, Cs is considered as the most electropositive element.
(b) Lithium cannot be used in making photoelectric cells because out of all the alkali metals it has the highest ionization energy and thus cannot emit electrons when exposed to light.
(c) Due to small size, lithium does not form alums
New answer posted
6 months agoContributor-Level 10
Beryllium carbonate is unstable and decomposes to give beryllium oxide and carbon dioxide.
New answer posted
6 months agoContributor-Level 10
The loosely held s-electron in the outermost valence shell of these elements makes them the most electropositive metals which readily give ions, M+ or M2+.
New answer posted
6 months agoContributor-Level 10
Li+ has maximum degree of hydration due to its small size and for this reason lithium salts are mostly hydrated.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 679k Reviews
- 1800k Answers
