Ncert Solutions Chemistry Class 11th
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10.7. Explain the following:
(a) Why Cs is considered as the most electropositive element?
(b) Lithium cannot be used in making photoelectric cells.
(c) Lithium does not form alums.
10.7. Explain the following:
(a) Why Cs is considered as the most electropositive element?
(b) Lithium cannot be used in making photoelectric cells.
(c) Lithium does not form alums.
(a) Due to its the lowest ionization energy, Cs is considered as the most electropositive element.
(b) Lithium cannot be used in making photoelectric cells because out of all the alkali metals it has the highest ionization energy and thus cannot emit electrons when exposed to light.
(c) Due to smal
10.6. Why Beryllium carbonate is kept in the atmosphere of carbon dioxide?
10.6. Why Beryllium carbonate is kept in the atmosphere of carbon dioxide?
Beryllium carbonate is unstable and decomposes to give beryllium oxide and carbon dioxide.
10.5. Why are s-block elements highly electropositive?
10.5. Why are s-block elements highly electropositive?
The loosely held s-electron in the outermost valence shell of these elements makes them the most electropositive metals which readily give ions, M+ or M2+.
Li+ has maximum degree of hydration due to its small size and for this reason lithium salts are mostly hydrated.
10.3. Why BeSO4 is soluble in water while BaSO4 is not?
10.3. Why BeSO4 is soluble in water while BaSO4 is not?
Hydration energy decreases down the group from Be to Ba and lattice energy remains almost constant.
10.2. What are group I elements and why are they known as the alkali metals?
10.2. What are group I elements and why are they known as the alkali metals?
Lithium, sodium, potassium, rubidium, caesium and Francium are group I elements and collectively known as the alkali metals.
They are called as the alkali metals because they form hydroxides on reaction with water which are strongly alkaline in nature.
Question Answers:
10.1. Explain the Diagonal Relationship betweenBeryllium and Aluminium.
Question Answers:
10.1. Explain the Diagonal Relationship betweenBeryllium and Aluminium.
The ionic radius of Be2+ is estimated to be 31 pm; the charge/radius ratio is nearly the same as that of the Al3+ ion. Hence beryllium resembles aluminium in some ways. Some ofthe similarities are:
(i) Like aluminium, beryllium is not readily attacked by acids because of the presence of an oxide fil
10.5. Arrange the following in the increasing order of solubility in water.
(a) MgCl2 < CaCl2< SrCl2< BaCl2
(b) BaCl2 < SrCl2 < CaCl2 <mgcl2</mgcl
(c) SrCl2 < MgCl2 < CaCl2 < BaCl2
(d) MgCl2 < CaCl2< BaCl2< SrCl2
10.5. Arrange the following in the increasing order of solubility in water.
(a) MgCl2 < CaCl2< SrCl2< BaCl2
(b) BaCl2 < SrCl2 < CaCl2 <mgcl2</mgcl
(c) SrCl2 < MgCl2 < CaCl2 < BaCl2
(d) MgCl2 < CaCl2< BaCl2< SrCl2
(b) BaCl2 < SrCl2 < CaCl2
10.5. Assertion: Electrode potential is a measure of the tendency of an element to lose electrons in the aqueous solution. So, the reducing property can be correlated in terms ofelectrode potentials (E°) of alkali metals.
Reason: More positive is the electrode potential, higher is the tendency of the element to loose electrons and hence, stronger is the reducing agent.
10.5. Assertion: Electrode potential is a measure of the tendency of an element to lose electrons in the aqueous solution. So, the reducing property can be correlated in terms ofelectrode potentials (E°) of alkali metals.
Reason: More positive is the electrode potential, higher is the tendency of the element to loose electrons and hence, stronger is the reducing agent.
(c) Reason is wrong a statement. More negative is the electrode potential, higher is the tendency of the element to lose electrons and hence, stronger is the reducing agent.