Ncert Solutions Chemistry Class 11th
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Extensive properties depend on the quantity of matter but intensive properties do not. Explain whether the following properties are extensive or intensive. Mass, internal energy, pressure, heat capacity, molar heat capacity, density, mole fraction, specific heat, temperature and molarity.
Extensive properties depend on the quantity of matter but intensive properties do not. Explain whether the following properties are extensive or intensive. Mass, internal energy, pressure, heat capacity, molar heat capacity, density, mole fraction, specific heat, temperature and molarity.
This is a Long Answer Type Questions as classified in NCERT Exemplar
A contrast is drawn in thermodynamics between extensive and intense qualities. An extensive property is one whose value is proportional to the amount or size of matter in the system. Extensive properties include mass, volume, intern
Assertion (A): Some metals like platinum and palladium, can be used as storage media for hydrogen.
Reason (R): Platinum and palladium can absorb large volumes of hydrogen.
(i) Statements A and R both are correct and R is the correct explanation of A.
(ii) A is correct but R is not correct.
(iii) A and R both are correct but R is not the correct explanation of A.
(iv) A and R both are false.
Assertion (A): Some metals like platinum and palladium, can be used as storage media for hydrogen.
Reason (R): Platinum and palladium can absorb large volumes of hydrogen.
(i) Statements A and R both are correct and R is the correct explanation of A.
(ii) A is correct but R is not correct.
(iii) A and R both are correct but R is not the correct explanation of A.
(iv) A and R both are false.
This is a assertion and reason answer type question as classified in NCERT Exemplar
(i) Statements A and R both are correct and R is the correct explanation of A. Since, metals like Pd and Pt adsorbs a large volume of hydrogen, hence, these are used as a storage media for it.
In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.
Assertion (A): Permanent hardness of water is removed by treatment with washing soda.
Reason (R): Washing soda reacts with soluble magnesium and calcium sulphate to form insoluble carbonates.
(i) Statements A and R both are correct and R is the correct explanation of A.
(ii) A is correct but R is not correct.
(iii) A and R both are correct but R is not the correct explanation of A.
(iv) A and R both are false.
In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.
Assertion (A): Permanent hardness of water is removed by treatment with washing soda.
Reason (R): Washing soda reacts with soluble magnesium and calcium sulphate to form insoluble carbonates.
(i) Statements A and R both are correct and R is the correct explanation of A.
(ii) A is correct but R is not correct.
(iii) A and R both are correct but R is not the correct explanation of A.
(iv) A and R both are false.
This is a assertion and reason answer type question as classified in NCERT Exemplar
(i) Statements A and R both are correct and R is the correct explanation of A.
MCl2+Na2CO3→ MCO3+2NaCl
MSO4+Na2CO3→MCO3+Na2SO4
Match the items in Column I with the relevant item in Column II.
Column I
Column II
(i) Hydrogen peroxide is used as a
(a) zeolite
(ii)Used in Calgon method
(b) perhydrol
(iii)Permanent hardness of hard water is removed by
(c) sodium hexametaphosphate
(d) propellant
Match the items in Column I with the relevant item in Column II.
|
Column I |
Column II |
|
(i) Hydrogen peroxide is used as a |
(a) zeolite |
|
(ii)Used in Calgon method |
(b) perhydrol |
|
(iii)Permanent hardness of hard water is removed by |
(c) sodium hexametaphosphate |
|
(d) propellant |
This is a matching answer type question as classified in NCERT Exemplar
(i) → (b); (ii) → (c); (iii) → (a)
Match the terms in Column I with the relevant item in Column II.
Column I
Column II
(i) Electrolysis of water produces
(a) atomic reactor
(ii)Lithium aluminum hydride is used as
(b) polar molecule
(iii)Hydrogen chloride is a
(c) recombines on metal surface to generate high temperature
(iv) Heavy water is used in
(d) reducing agent
(v) Atomic hydrogen
(e) hydrogen and oxygen
Match the terms in Column I with the relevant item in Column II.
|
Column I |
Column II |
|
(i) Electrolysis of water produces |
(a) atomic reactor |
|
(ii)Lithium aluminum hydride is used as |
(b) polar molecule |
|
(iii)Hydrogen chloride is a |
(c) recombines on metal surface to generate high temperature |
|
(iv) Heavy water is used in |
(d) reducing agent |
|
(v) Atomic hydrogen |
(e) hydrogen and oxygen |
This is a matching answer type question as classified in NCERT Exemplar
(i)→ (e); (ii)→ (d); (iii)→ (b); (iv)→ (a); (v)→ (c)
Match Column I with Column II for the given properties/applications mentioned therein.
Column I
Column II
(i) H
(a) Used in the name of perhydrol.
(ii)H2
(b) Can be reduced to dihydrogen by NaH.
(iii)H2O
(c) Can be used in hydroformylation of olefin.
(iv) H2O2
(d) Can be used in cutting and welding.
Match Column I with Column II for the given properties/applications mentioned therein.
|
Column I |
Column II |
|
(i) H |
(a) Used in the name of perhydrol. |
|
(ii)H2 |
(b) Can be reduced to dihydrogen by NaH. |
|
(iii)H2O |
(c) Can be used in hydroformylation of olefin. |
|
(iv) H2O2 |
(d) Can be used in cutting and welding. |
This is a matching answer type question as classified in NCERT Exemplar
(i)→ (d); (ii)→ (b); (iii)→ (c); (iv)→ (a)
Correlate the items listed in Column I with those listed in Column II. Find out as many correlations as you can.
Column I
Column II
(i) Synthesis gas
a. Na2[Na4(PO3)6]
(ii) Dihydrogen
(b) Oxidising agent
(iii) Heavy water
(c) Softening of water
(iv) Calgon
(d) Reducing agent
(v) Hydrogen peroxide
(e) Stoichiometric compounds of s-block elements
(vi) Salt like hydrides
(f) Prolonged electrolysis of water
(g) Zn + NaOH
(h) Zn + dil. H2SO4
(i) Synthesis of methanol
(j) Mixture of CO and H2
Correlate the items listed in Column I with those listed in Column II. Find out as many correlations as you can.
|
Column I |
Column II |
|
(i) Synthesis gas |
a. Na2[Na4(PO3)6] |
|
(ii) Dihydrogen |
(b) Oxidising agent |
|
(iii) Heavy water |
(c) Softening of water |
|
(iv) Calgon |
(d) Reducing agent |
|
(v) Hydrogen peroxide |
(e) Stoichiometric compounds of s-block elements |
|
(vi) Salt like hydrides |
(f) Prolonged electrolysis of water |
|
(g) Zn + NaOH |
|
|
(h) Zn + dil. H2SO4 |
|
|
(i) Synthesis of methanol |
|
|
(j) Mixture of CO and H2 |
This is a matching answer type question as classified in NCERT Exemplar
(i) → (j); (ii) → (h); (iii) → (f) : (iv) → (a); (v) → (b); (vi) → (e)
Which of the following statements is correct?
(i) Metallic hydrides are deficient in hydrogen.
(ii) Metallic hydrides conduct heat and electricity.
(iii) Ionic hydrides do not conduct electricity in solid state.
(iv) Ionic hydrides are very good conductors of electricity in solid state.
Which of the following statements is correct?
(i) Metallic hydrides are deficient in hydrogen.
(ii) Metallic hydrides conduct heat and electricity.
(iii) Ionic hydrides do not conduct electricity in solid state.
(iv) Ionic hydrides are very good conductors of electricity in solid state.
This is a multiple choice answer as classified in NCERT Exemplar
Option (i), (ii) and (iii)
Ionic hydrides are crystalline, non-volatile and non-conducting in solid state
Which of the following statements is correct?
(i) Hydrides of group 13 act as Lewis acids.
(ii) Hydrides of group 14 are electron deficient hydrides.
(iii) Hydrides of group 14 act as Lewis acids.
(iv) Hydrides of group 15 act as Lewis bases.
Which of the following statements is correct?
(i) Hydrides of group 13 act as Lewis acids.
(ii) Hydrides of group 14 are electron deficient hydrides.
(iii) Hydrides of group 14 act as Lewis acids.
(iv) Hydrides of group 15 act as Lewis bases.
This is a multiple choice answer as classified in NCERT Exemplar
Option (i) and (iv)
All elements in group 13 are Lewis acids because they form electron-deficient compounds. Excess electrons are found as lone pairs in electron-rich hydrides.
These compounds are made up of elements from groups 15-17. (N
Which of the following statements is correct?
(i) Elements of group 15 form electron deficient hydrides.
(ii) All elements of group 14 form electron precise hydrides.
(iii) Electron precise hydrides have tetrahedral geometries.
(iv) Electron rich hydrides can act as Lewis acids.
Which of the following statements is correct?
(i) Elements of group 15 form electron deficient hydrides.
(ii) All elements of group 14 form electron precise hydrides.
(iii) Electron precise hydrides have tetrahedral geometries.
(iv) Electron rich hydrides can act as Lewis acids.
This is a multiple choice answer as classified in NCERT Exemplar
Option (ii) and (iii)
Electron precise hydrides have the required number of electrons to write their conventional Lewis structures. All elements of group 14 form such compounds (e.g., CH4) which are tetrahedral in geometry.