Ncert Solutions Chemistry Class 12th

$C{H}_{3}C{H}_{2}C{H}_{2}Br\stackrel{Mg}{\to }C{H}_{3}C{H}_{2}C{H}_{2}MgBr\stackrel{C{O}_2}{\to }$

$C{H}_{3}C{H}_{2}C{H}_{2}COOMgBr\stackrel{H_3{O}^{+}}{\to }C{H}_{3}C{H}_{2}C{H}_{2}COOH\left(butanoicacid\right)$

O₂F₂ oxidises plutonium to PuF₆ and the reaction is used in removing plutonium as PuF₆ from spent nuclear fuel.

When red phosphorus is heated in a sealed tube at 803 K, a - black phosphorus is formed.

Let molarity of KMnO₄ = x

$KMn{O}_4+FeS{O}_4\to F{e}_2{\left(S{O}_4\right)}_3+M{n}^{2+}$

n = 5         n = 1         Ferric sulphate

equivalent of KMnO₄ = equivalent of FeSO₄

5 * x * 10 = 1 * 0.1 * 10

x = 0.02 M

Strength = (0.02 * 158) = 3.16g/L

= 316 * 10^-2 g/L

Ans. = 316

$\underset{\left(z=93\right)}{Np}\Rightarrow 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^2$

$4d^{10}5p^{6}6s^{2}4f^{14}5d^{10}6p^{6}7s^{2}5f^{4}6d^1$

Total number of f-electrons = 14 + 4 = 18 electrons

Ans. = 18

Dumas method,

Moles of N in N, N-dimethylaminopentane (C₇H₁₇N)

$=\frac{57.5}{115}=0.5mole$

$C_7{H}_{17}N+\frac{45}{2}CuO\to 7C{O}_2+\frac{17}{2}{H}_{2}O+\frac{1}{2}{N}_2+\frac{45}{2}Cu$

$\frac{n_{CuO}}{\left(\frac{45}{2}\right)}=\frac{n_{c_7{H}_{17}N}}{1}$

$n_{CuO}=\left(\frac{45}{2}\right)*0.5mol$

= 11.25 mol

= 1125 * 10^-2 mol

Ans. = 1125