Ncert Solutions Maths class 12th
Get insights from 2.5k questions on Ncert Solutions Maths class 12th, answered by students, alumni, and experts. You may also ask and answer any question you like about Ncert Solutions Maths class 12th
- 2.5k
Questions
- 0
Discussions
- 0
Active Users
- 65
Followers
Have a question about Ncert Solutions Maths class 12th? Ask our experts
Keep it short & simple. Type complete word. Avoid abusive language.
The equation of the plane which contains the y-axis and passes through the point (1,2,3) is:
The equation of the plane which contains the y-axis and passes through the point (1,2,3) is:
Let the equation of the plane passing through (1, 2, 3) be:
a (x - 1) + b (y - 2) + c (z - 3) = 0
The plane contains the y-axis, which has direction ratios (0, 1, 0).
Therefore, the normal to the plane must be perpendicular to the y-axis.
a (0) + b (1) + c (0) = 0 ⇒ b = 0
The equation becomes: a (x -
Four fair dice are thrown independently 27 times. Then the expected number of times, at least two dice show up a three or a five, a
Four fair dice are thrown independently 27 times. Then the expected number of times, at least two dice show up a three or a five, a
P (at least 2 show 3 or 5) =? C? (2/6)² (4/6)² +? C? (2/6)³ (4/6)¹ +? C? (2/6)?
= (384+128+16)/6? = 11/27
n=27
∴ expectation of number of times = np
= 27 ⋅ (11/27) = 11
The probability of a man hitting a target is 1/10. The least number of shots required, so that the probability of his hitting the target at least once is greater than 1/4, is
(Probability)
The probability of a man hitting a target is 1/10. The least number of shots required, so that the probability of his hitting the target at least once is greater than 1/4, is
(Probability)
We have, 1 - (probability of all shots result in failure) > 1/4
? 1 - (9/10)? > 1/4
? 3/4 > (9/10)? ? n? 3 > (9/10)? ? n? 3
The probabilities of three events A, B and C are given by P(A) = 0.6, P(B) = 0.4 and P(C) = 0.5. If P(A ∪ B) = 0.8, P(A ∩ C) = 0.3, P(A ∩ B ∩ C) = 0.2, P(B ∩ C) = β and P(A ∪ B ∪ C) = α, where 0.85 ≤ α ≤ 0.95, then β lies in the interval:
<!-- [if !supportLineBreakNewLine]-->
<!--[endif]-->
The probabilities of three events A, B and C are given by P(A) = 0.6, P(B) = 0.4 and P(C) = 0.5. If P(A ∪ B) = 0.8, P(A ∩ C) = 0.3, P(A ∩ B ∩ C) = 0.2, P(B ∩ C) = β and P(A ∪ B ∪ C) = α, where 0.85 ≤ α ≤ 0.95, then β lies in the interval:
<!-- [if !supportLineBreakNewLine]-->
<!--[endif]-->
P (A∪B∪C) = P (A) + P (B) + P (C) – P (A∩B) – P (B∩C) – P (C∩A) + P (A∩B∩C)
Given relations lead to: α = 1.4 – P (A∩B) – β ⇒ α + β = 1.4 - P (A∩B)
Again, from P (A∪B) = P (A) + P (B) – P (A∩B), and given values, it is found that P (A∩B) = 0.2.
From (1) and (2), α = 1.2 – β.
Now given 0.85 ≤ α ≤ 0.95
⇒ 0.
Let λεR. The system of linear equations.
2x₁ – 4x₂ + λx₃ = 1
x₁ - 6x₂ + x₃ = 2
λx₁ – 10x₂ + 4x₃ = 3
Is inconsistent for:
Let λεR. The system of linear equations.
2x₁ – 4x₂ + λx₃ = 1
x₁ - 6x₂ + x₃ = 2
λx₁ – 10x₂ + 4x₃ = 3
Is inconsistent for:
Here D = | 2 -4 λ |
| 1 -6 1 | = (λ-3) (3λ+2)
| λ -10 4 |
D = 0 ⇒ λ = 3, -2/3
A plane P meets the coordinate axes at A, B and C respectively. The centroid of ? ABC is given to be (1,1,2). Then the equation of the line through this centroid and perpendicular to the plane P is:
<!-- [if !supportLineBreakNewLine]-->
<!--[endif]-->
A plane P meets the coordinate axes at A, B and C respectively. The centroid of ? ABC is given to be (1,1,2). Then the equation of the line through this centroid and perpendicular to the plane P is:
<!-- [if !supportLineBreakNewLine]-->
<!--[endif]-->
Let A (α, 0,0), B (0, β, 0), C (0,0, γ), then the centroid is G (α/3, β/3, γ/3) = (1,1,2).
α = 3, β = 3, γ = 6
∴ Equation of plane is x/α + y/β + z/γ = 1
⇒ x/3 + y/3 + z/6 = 1
⇒ 2x + 2y + z = 6
∴ Required line passing through G (1,1,2) and normal to the plane is (x-1)/2 = (y-1)/2 = (z-2)/1.
If the tangent to the curve, y = f(x) = xlog? x, (x > 0) at a point (c, f(c)) is parallel to the line - segment joining the points (1,0) and (e, e) then c is equal to:
<!-- [if !supportLineBreakNewLine]-->
<!--[endif]-->
If the tangent to the curve, y = f(x) = xlog? x, (x > 0) at a point (c, f(c)) is parallel to the line - segment joining the points (1,0) and (e, e) then c is equal to:
<!-- [if !supportLineBreakNewLine]-->
<!--[endif]-->
f' (c) = 1 + lnc = e/ (e-1)
lnc = e/ (e-1) - 1 = (e - (e-1)/ (e-1) = 1/ (e-1)
c = e^ (1/ (e-1)
The set of all real values of λ for which the function f(x) = (1 - cos²x) ⋅ (λ + sinx), x ∈ (-π/2, π/2), has exactly one maxima and exactly one minima, is
<!-- [if !supportLineBreakNewLine]-->
<!--[endif]-->
The set of all real values of λ for which the function f(x) = (1 - cos²x) ⋅ (λ + sinx), x ∈ (-π/2, π/2), has exactly one maxima and exactly one minima, is
<!-- [if !supportLineBreakNewLine]-->
<!--[endif]-->
f (x) = sin²x (λ + sinx)
f' (x) = 2sinxcosx (λ + sinx) + sin²x (cosx) = sinxcosx (2λ + 3sinx)
For extrema, f' (x) = 0
sinx = 0, cosx = 0, or sinx = -2λ/3
For more than 2 points of extrema in the interval, sinx = -2λ/3 must have solutions other than where sinx=0 or cosx=0.
-1 < -2λ/3 < 1 and -2λ/3 ≠ 0
This gives λ ∈ (-3/2, 3/2) -

