Ncert Solutions Maths class 12th

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New answer posted•a year ago
S
a year ago

(5/3, 7/3, 17/3)
AD ⋅ PD = 0
((5/3-α)i?+(7/3-7)j?+(17/3-1)k?) . (2/3i?+7/3j?+8/3k?) = 0
(5/3-α)(2/3) + (-14/3)(7/3) + (14/3)(8/3) = 0
A(α, 7, 1) D(7/3, 7/3, 12/3)
⇒ 3α = 12
α = 4

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New answer posted•a year ago
S
a year ago

 Δ = |1 1 1| = 0
|1 2 3|
|3 2 λ|
⇒ 1(2λ - 6) - 1(λ - 9) + 1(-4) = 0
⇒ λ = 1
Δx = |6 1 1|
|10 2 3| = 0
|μ 2 λ|
⇒ 2λ + μ = 16
⇒ μ = 14
μ - λ² = 14 - 1 = 13

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New answer posted•a year ago
S
a year ago

6.00
b·a = c·a
|a+b-c|² = |a|²+|b|²+|c|²+2(a·b - b·c - a·c)
= 4+16+16+2(a·b - 0 - a·b) = 36
⇒ |a+b-c| = 6

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New answer posted•a year ago
New answer posted•a year ago
New answer posted•a year ago
S
a year ago

Line are coplanar
so | [α, 5-α, 1], [2, -1, 1], | = 0
−5α + (α – 5)3 + 7 = 0
-2α = 8 ⇒ α = −4
⇒ L? : (x+2)/-4 = (y+1)/9 = (z+1)/1
Now by cross checking option (A) is correct.

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New answer posted•a year ago
S
a year ago

w = I + j - 3k
p = 3i - j + k
q = -3i + 2j + 4k
p × q = |i, j, k; 3, -1, 1; -3, 2, 4| = -6i - 15j + 3k
S.D. = |AD. (p × q)|/|p × q| = | (36+225+9)|/√ (36+225+9) = 3√30

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New answer posted•a year ago
S
a year ago

Differentiating

y.  - 2 x 2 1 - x 2 + 1 - x 2 ⋅ y ' = x ⋅ 2 y y ' 2 1 - y 2 - 1 - y 2

Put x = 1 2 , y = - 1 4 and x , y = - 1 8

y ' = - 5 2

...Read more

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New answer posted•a year ago
S
a year ago

dy/dx = 2y/ (xlnx).
dy/y = 2dx/ (xlnx).
ln|y| = 2ln|lnx| + C.
ln|y| = ln (lnx)²) + C.
y = A (lnx)².
(ln2)² = A (ln2)². ⇒ A=1.
y = f (x) = (lnx)².
f (e) = (lne)² = 1² = 1.

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New answer posted•a year ago
S
a year ago

P (at least one head) = 1 - P (no heads) = 1 - (1/2)? ≥ 0.9.
0.1 ≥ (1/2)?
10 ≤ 2?
n=3, 2³=8. n=4, 2? =16.
Minimum value of n is 4.

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