NIT

PLACEMENT WING:
The placements were good and companies were adequate. Many companies like Reliance Jio, L&T, L&T Infotech, National Stock Exchange Infotech and Mu Sigma had visited for placement drives and about 70 percent of the final-year students got selected. All the companies offered an average package of 3.5 Lacs per annum. Snapdeal offered 15 Lacs per annum and 2 students bagged it. I got a package of 3.5 Lacs.
5/10.

Hello,
I hope you are doing well. Don't go for a branch, go for a college. You can check the list of colleges including NITs and IIITs that you can get according to your marks and rank. Use Shiksha JEE College predictor:
https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor?utm_source=connect&utm_medium=CR_JEECP&utm_campaign=7489993

Yes, you can get but you have to crack the JEE Mains entrance exam.

There is a slight probability of getting into an NIT. The admission into an NIT also depends upon the home state of the candidate. Home state is the state where one did the class 11 and class 12. Please check out the following link for the opening and closing ranks in various institutes last year : https://josaa.nic.in/webinfocms/public/view.aspx?page=46. However, do not get disappointed if you don't get admission into an NIT. There are several other good institutes.
All the best!

Hello,
I hope you are doing well. No you can't give AAT examination because you didn't even clear the cutoff of JEE Advanced. The minimum criteria for getting into AAT is to clear the JEE Advanced cut-off. You should go for NITs.

NIT kurukshetra is better.

The cutoff marks declared with the JEE Mains result is required to take part in JEE Advance and NITs can be secured by generally 50 to 60 marks greater than the cutoff.

This is true in case of all NITs but not in case of IIITs. With below 1 lac income, you don't have to give tuition fee.

Go to jossa website, you will find everything there. The link is:
https://josaa.nic.in/webinfocms/Public/View.aspx?page=71
Here you can get the answer of your question.