Organic Chemistry - Some Basic Principles and Tech

(b) Is the most stable since it is a tertiary carbocation.

(b) Iron (III) hexacyanidoferrate (II) (or ferriferrocyanide) Fe₄ [Fe (CN)₆]₃  is the correct answer.

Mass of the compound = 0.468 g
Mass of barium sulphate= 0.668 g

% of sulphur = 

                     

Mass of the compound = 0.3780 g
Mass of silver chloride = 0.5740 g

% of chlorine =

Step I: Calculation of volume of unused acid i.e. V2 =?

V1 = Volume of NAOH solution required = 60 cm³ 

N1 = Normality of NaOH solution = ½ N

N2 = Normality of H₂SO₄ = 1N

Applying N1V1 = N2V2

½ N x 60 cm³ = 1N x V2

Or V2 = 30 cm³

Step II: calculation of volume of acid used

Volume of acid added = 50 cm³

Volume of unused acid = 30 cm³

Volume of acid used = 50 – 30 = 20 cm³

Step III: Calculation of % of nitrogen

Mass of compound = 0.50 g

Volume of acid used = 20 cm³

Normality of acid used = 1 N

% of nitrogen = (1.4 x 20 x 1) / 0.50 = 56%

Step 1: Calculation of mass of CO₂ produced

Mass of compound = 0.20 g

% of carbon = 69%

i.e. 12/44 x  = Mass of Carbondioxide formed / Mass of Compound = 69/100

Therefore, mass of CO₂formed = (69 x 44 x 0.20) / (12 x 100) = 0.506 g

Step 2: Calculation of mass of H₂O produced

Mass of compound = 0.20 g

% of hydrogen = 4.8%

i.e. 2/18 x Mass of Water Formed/Mass of Compound = 4.8/100

Therefore, mass of H₂O formed = 4.8*18*0.20/2*100 = 0.0864 g

It necessary to use acetic acid and not sulphuric acid for acidification of sodium extract for testing sulphur by lead acetate test because sulphuric acid will react with lead acetate to form a white precipitate of lead sulphate which will interfere in the test of sulphur.

Pb (OCOCH₃)₂ + H₂SO₄ →PbSO₄  + 2CH₃COOH

CO₂ is acidic in nature and therefore, it reacts with the strong base KOH to form K₂CO₃.

2KOH + CO₂ ? K₂CO₃+ H₂O.

No. CCl₄ is a completely non-polar covalent compound whereas AgNO₃ is ionic in nature. Therefore, they are not expected to react and thus a white precipitate of silver chloride will not be formed.