P Block Elements

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7 months ago

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alok kumar singh

Contributor-Level 10

7.34

It is difficult to study the chemistry of radon because it is a radioactive substance having a half-life (the time period to decompose the substance half to its initial concentration) of only 3.82 days.

Radon belongs to the 18 group elements with chemical formula as Rn. In general, the elements at the bottom o periodic table are radioactive, they are very dangerous to study as they emit harmful radiations.

Also, compounds of radon such as RnF2 have not been isolated, they are still in the phase of discovery. They have only been identified by radiotracer technique and no any further properties have been determined.

New answer posted

7 months ago

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alok kumar singh

Contributor-Level 10

7.33

XeF6 + H2O  XeO2F2 + HF

Balanced equation: XeF6 + 2H2O XeO2F2 +4HF. The steps for balancing the reaction are as follows:

1. The main element is First, check if the atoms of Xe on both sides are balanced. YES, they are.

2. Then take another element i.e. F. It is not balanced on the right side, there are 3 atoms of F missing. So, to balance it multiply HF by 4.

3. Now check the other secondary atoms which are oxygen and hydrogen. Oxygen is not balanced on the left side as there are 2 O atoms so multiply H2O by

4. Now check for the hydrogen They are balanced on both sides.

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7 months ago

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alok kumar singh

Contributor-Level 10

7.32

Helium mixed with oxygen under pressure is given to sea divers for respiration because pure oxygen can be toxic at a great concentration at the depth. Therefore oxygen can be mixed with helium to reduce oxygen concentration while eliminating nitrogen. 

The main reason for adding helium to the breathing mix is to reduce the proportion of nitrogen and oxygen below those of air, to allow the gas mix to be breathed safely on deep dives.

A low proportion of nitrogen is required to reduce nitrogen narcosis and other physiological effects of gas at depth.

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7 months ago

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alok kumar singh

Contributor-Level 10

7.31

In interhalogen compound ICl and I2 the atoms are bonded by covalent bonds

Reactivity refers to the rate at which a chemical species will undergo reaction in time. For reaction to take place the compound needs to be broken into separate elements first, then the individual elements react with other elements to form new compounds. So any compound which can easily break into their individual elements can react faster.

The covalent bonds between dissimilar atoms I and Cl atoms in ICl are weaker than between similar atoms in I2. Therefore the bond between ICL will break easily so the I and Cl atom will be easily available to form another

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7 months ago

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alok kumar singh

Contributor-Level 10

7.30

Two poisonous gases that can be prepared with chlorine gas are:

Phosgene (COCl2)

This is how phosphene is formed:

CO + Cl2? COCl2 (in presence of sunlight)

(ii) Mustard gas (Cl-C2H4-S-C2H4-Cl)

(iii) Tear gas (CCl3NO2)

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7 months ago

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alok kumar singh

Contributor-Level 10

7.29

Moist chlorine is a good reducing agent because it can accept electrons from other species as it is very electronegative.

(iii) The bleaching action of chlorine is due to oxidation by nascent oxygen produced. This nascent oxygen can be produced by

Chlorine dissolves in water in absence of sunlight and forms hydrochloric acid and hypochlorous acid (HOCl)

Since hypochlorous acid is not much stable it decomposes giving nascent oxygen. Cl2 + H2O  HCl + HOCl

HOCl HCl + [O]

This [O] is called as nascent oxygen. This nascent oxygen is responsible for bleaching action.

NOTE: Since chlorine has the ability to kill harmful micro-organism it

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7 months ago

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alok kumar singh

Contributor-Level 10

7.28

Sea water is a treasure of many elements and halogens are one of them. It contains many compounds of halogen including bromides, iodides, and chlorides. The solid deposits from sea water contain NaCl and Carnalite.

It primarily contains COMMON SALT (2.5% by mass). The deposits of dried up sea bed also contain sodium chloride and Carnallite, KCl.MgCl2.6H2O .

The Marine life also contains iodine in their systems. For example, sea weed may contain 0.5% iodine as sodium iodide (NaI) and Chile saltpetre (sodium compound) contains about 0.3% of sodium iodate. Thus, the sea is the greatest source of halogens.

New answer posted

7 months ago

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alok kumar singh

Contributor-Level 10

7.27

The reasons for the anomalous behaviour of fluorine are as follows:

The smallest size of fluorine

The highest electronegativity

Low bond dissociation enthalpy of F-F bond

Non-availability of d-orbitals in its valence shell The anomalous properties are as follows;

Fluorine shows only one oxidation state-1 while all other halogens show variable oxidation states like

-1, +1, +3, +5, +7 (due to small size, high electronegativity)

Fluorine forms strong hydrogen bonding in its hydrides unlike other halogens. (due to high hydration energy than other elements)

The compounds of fluorine have higher ionic character than other halogens. (due to high

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7 months ago

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alok kumar singh

Contributor-Level 10

7.26

The oxidizing power of an element depends on three factors.

1. Bond dissociation energy

2. Electron gain enthalpy

3. Hydration enthalpy

Fluorine is considered the strongest oxidizing agent compared to all known elements due to its small size (being the first member of 17 group and ionic radii decrease downwards), low bond enthalpy of F-F (due to high electron-electron repulsion).

High negative value of electron gain enthalpy (the highest electronegativity ) and very high hydration energy of F- ions (hydration energy is the energy released when a compound is dissolved in water .

 In case of fluorine it is more due to the strong inter

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7 months ago

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alok kumar singh

Contributor-Level 10

7.25

H2SO4 is dibasic acid (two replacable H+ ions) . In aqueous solution it dissociates in two steps as follows:

H2SO4 + H2O H3O+ + HSO4

(Ka1 = very large)

HSO4 + H2O H3O+ + SO42

(Ka2 = 1.2 x 10–2)

The formula for dissociation constants are:

The neutral H2SO4 molecule has more tendency to lose a proton (H+) than the Lowry-Bronsted base (which can donate electron i.e. accept a proton H+) HSO -.

This is because a neutral has a much higher tendency to lose a proton than the negatively charged. Thus, the former is a much stronger acid than the latter.

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