P Block Elements

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

NO2 exists as a monomer with one unpaired electron in the gaseous state, but it dimerises to N2O4 in the solid state, leaving no unpaired electron, making the solid form diamagnetic.

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

Three P—Cl bonds are arranged in one plane at a 1200 angle. These bonds are known as equatorial bonds because they are formed between two points. The remaining two P—Cl bonds, one above the equatorial plane and the other below it, form  90° angle with the plane. Axial bonds are the name for these types of bonds. Because axial bond pairs are subjected to greater repulsive interaction than equatorial bond pairs, axial bonds are slightly longer and hence slightly weaker than equatorial bonds, making the PCl5 molecule more reactive.

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

PH3 is insoluble in water and cannot create hydrogen bonds with it, it forms bubbles, whereas NH3 dissolves because it is soluble in water and can form hydrogen bonds with it.

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

4NH3 + 5O2 4NO + 6H2O

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Payal Gupta

Contributor-Level 10

This is a short answer type question as classified in NCERT Exemplar

SO3 generates a dense fog of sulphuric acid that does not condense quickly, it is not absorbed directly in water to form H2SO4.

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Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

A = NH4NO2

B = N2

C = NH3

D = HNO3 

(i) NH4NO2→N2 + 2H2O

(ii) N2 + 3H2→2NH3

(iii) 4NH3 + 5O2→4NO + 6H2O

4NO + O2→4NO2

3NO2 + H2O→2HNO3 + NO 

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Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

Here, 'A' is NO2 (Nitrogen dioxide)

'B' is N2O4 (dinitrogen tetraoxide)

'C' is N2O3 (dinitrogen trioxide)

A brown gas is produced when lead nitrate (II) is heated

2Pb (NO3)2 2PbO  +  4NO2 + O2

2NO2 N2O4

2NO  + N2O4 2N2O3 

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Payal Gupta

Contributor-Level 10

This is a long answer type question as classified in NCERT Exemplar

'A' is S8 'B' is SO2 gas

 S8 + 8O2 8SO2

2MnO4 + 5SO2 + 2H2O → 5 SO42– + 4H+ + 2Mn2+

(violet)                                                              (colourless)

2Fe3+ + SO2 + 2H2O → 2Fe2+ + SO42– + 4H+

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A
alok kumar singh

Contributor-Level 10

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As Bond dissociation energy generally decreases on moving down the group as the atomic size of the element increases. However, among halogens, the bond dissociation energy of F2 is lower than that of Cl2 and F2 due to the small atomic size of

Thus increasing order for bond dissociation energy among halogens is as follows:I22

As Bond dissociation energy of H-X molecules where X is the halogen decreases with increase in the atomic HI is the strongest acid as it loses H atom easily due to weak bonding between H and I.

So Increasing acid strength is as follows: HF

Basic strength decreases as we move from Nitrogen to Bismuth down the group

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