P Block Elements
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New answer posted
4 months agoContributor-Level 10
7.29
Moist chlorine is a good reducing agent because it can accept electrons from other species as it is very electronegative.
(iii) The bleaching action of chlorine is due to oxidation by nascent oxygen produced. This nascent oxygen can be produced by
Chlorine dissolves in water in absence of sunlight and forms hydrochloric acid and hypochlorous acid (HOCl)
Since hypochlorous acid is not much stable it decomposes giving nascent oxygen. Cl2 + H2O HCl + HOCl
HOCl HCl + [O]
This [O] is called as nascent oxygen. This nascent oxygen is responsible for bleaching action.
NOTE: Since chlorine has the ability to kill harmful micro-organism it
New answer posted
4 months agoContributor-Level 10
7.28
Sea water is a treasure of many elements and halogens are one of them. It contains many compounds of halogen including bromides, iodides, and chlorides. The solid deposits from sea water contain NaCl and Carnalite.
It primarily contains COMMON SALT (2.5% by mass). The deposits of dried up sea bed also contain sodium chloride and Carnallite, KCl.MgCl2.6H2O .
The Marine life also contains iodine in their systems. For example, sea weed may contain 0.5% iodine as sodium iodide (NaI) and Chile saltpetre (sodium compound) contains about 0.3% of sodium iodate. Thus, the sea is the greatest source of halogens.
New answer posted
4 months agoContributor-Level 10
7.27
The reasons for the anomalous behaviour of fluorine are as follows:
The smallest size of fluorine
The highest electronegativity
Low bond dissociation enthalpy of F-F bond
Non-availability of d-orbitals in its valence shell The anomalous properties are as follows;
Fluorine shows only one oxidation state-1 while all other halogens show variable oxidation states like
-1, +1, +3, +5, +7 (due to small size, high electronegativity)
Fluorine forms strong hydrogen bonding in its hydrides unlike other halogens. (due to high hydration energy than other elements)
The compounds of fluorine have higher ionic character than other halogens. (due to high
New answer posted
4 months agoContributor-Level 10
7.26
The oxidizing power of an element depends on three factors.
1. Bond dissociation energy
2. Electron gain enthalpy
3. Hydration enthalpy
Fluorine is considered the strongest oxidizing agent compared to all known elements due to its small size (being the first member of 17 group and ionic radii decrease downwards), low bond enthalpy of F-F (due to high electron-electron repulsion).
High negative value of electron gain enthalpy (the highest electronegativity ) and very high hydration energy of F- ions (hydration energy is the energy released when a compound is dissolved in water .
In case of fluorine it is more due to the strong inter
New answer posted
4 months agoContributor-Level 10
7.25
H2SO4 is dibasic acid (two replacable H+ ions) . In aqueous solution it dissociates in two steps as follows:
H2SO4 + H2O H3O+ + HSO4 | (Ka1 = very large) |
HSO4 + H2O H3O+ + SO42 | (Ka2 = 1.2 x 10–2) |
The formula for dissociation constants are:

The neutral H2SO4 molecule has more tendency to lose a proton (H+) than the Lowry-Bronsted base (which can donate electron i.e. accept a proton H+) HSO -.
This is because a neutral has a much higher tendency to lose a proton than the negatively charged. Thus, the former is a much stronger acid than the latter.
New answer posted
4 months agoContributor-Level 10
7.24
Contact process consists of three steps. First is the burning of sulphide ores to form SO2 The second step (key step) is SO2 is oxidised to SO3 by heating the mixture on the heterogeneous catalyst V2O5.

Now, this step is very crucial for maximising the yield of H2SO4 It can be done by controlling the temperature and pressure of reaction.
The forward reaction is exothermic and there is a decrease in a number of moles and As Le- Chatelier principle states that when a system experiences a disturbance (concentration, pressure changes) it will respond to nullify the changes produced to bring initial condition.
So, when we decrease temperat
New answer posted
4 months agoContributor-Level 10
7.23
H2SO4 is one the most important and widely used chemicals for many purposes. It has following uses:
As an electrolyte sulphuric acid dissociates in aqueous solution to form ions. These ions are responsible for the conduction of electricity. As a result, sulphuric acid is used in the manufacture of the lead storage battery.
As a dehydrating agent (to remove water) because it has a great affinity for water. It doesn't get dissolved in water but absorb it, so it is used as a drying
For removing layers of basic oxides from the metal surfaces like iron, copper, before the metals are galvanized, electroplated. Because when the metals
New answer posted
4 months agoContributor-Level 10
7.22
When SO2 is passed through acidified potassium permanganate (VII) solution it decolourises the solution. This can be used for the detection of the SO2 gas. The below reaction represents the test,
5SO2 + 2MnO4 - + 2H2O? 5SO4 2- + 4H+ + 2Mn2+
New answer posted
4 months agoContributor-Level 10
7.21
The electronic configuration of S is 1s2 2s2 2p6 3s2 3p4.
One electron from 3p orbital goes to the 3d orbital and S undergoes sp2 hybridization, during the formation of SO2 molecule. Two of these orbitals form sigma bonds with two oxygen atoms and the third contains a lone pair of electrons.
The p-orbital and d-orbital contain an unpaired electron each. An electron in the p-orbital forms p π- p π bond with one oxygen atom and the other electron forms p π- d π bond with the other oxygen.
This is the reason SO2 has a bent structure. Also, it is a resonance hybrid of structures I and II, with equal bond lengths of 143pm.
New answer posted
4 months agoContributor-Level 10
7.20
SO2 acts as a reducing agent when passed through an aqueous solution containing Fe (III) salt. It reduces Fe (III) to Fe (II) i.e., ferric ions to ferrous ions.
2Fe3+ + SO2 + 2H2O? 2Fe2+ + SO4 2- + 4H+
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