P Block Elements
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7.24 Write the conditions to maximise the yield of H2SO4 by Contact process.
7.24 Write the conditions to maximise the yield of H2SO4 by Contact process.
7.24
Contact process consists of three steps. First is the burning of sulphide ores to form SO2 The second step (key step) is SO2 is oxidised to SO3 by heating the mixture on the heterogeneous catalyst V2O5.

Now, this step is very crucial for maximising the yield of H2SO4 It can be done by controlling
7.23 Mention three areas in which H2SO4 plays an important role.
7.23 Mention three areas in which H2SO4 plays an important role.
7.23
H2SO4 is one the most important and widely used chemicals for many purposes. It has following uses:
As an electrolyte sulphuric acid dissociates in aqueous solution to form ions. These ions are responsible for the conduction of electricity. As a result, sulphuric acid is used in the manufac
7.22
When SO2 is passed through acidified potassium permanganate (VII) solution it decolourises the solution. This can be used for the detection of the SO2 gas. The below reaction represents the test,
5SO2 + 2MnO4 - + 2H2O? 5SO4 2- + 4H+ + 2Mn2+
7.21 Comment on the nature of two S–O bonds formed in SO2 molecule. Are the two S–O bonds in this molecule equal ?
7.21 Comment on the nature of two S–O bonds formed in SO2 molecule. Are the two S–O bonds in this molecule equal ?
7.21
The electronic configuration of S is 1s2 2s2 2p6 3s2 3p4.
One electron from 3p orbital goes to the 3d orbital and S undergoes sp2 hybridization, during the formation of SO2 molecule. Two of these orbitals form sigma bonds with two oxygen atoms and the third contains a lone pair of electrons.
The
7.20 What happens when sulphur dioxide is passed through an aqueous solution of Fe(III) salt?
7.20 What happens when sulphur dioxide is passed through an aqueous solution of Fe(III) salt?
7.20
SO2 acts as a reducing agent when passed through an aqueous solution containing Fe (III) salt. It reduces Fe (III) to Fe (II) i.e., ferric ions to ferrous ions.
2Fe3+ + SO2 + 2H2O? 2Fe2+ + SO4 2- + 4H+
7.19
One of the quantitative method for estimating O3 gas is when ozone reacts with an excess of potassium iodide solution buffered with a borate buffer (pH 9.2), iodine is liberated. This iodine can be titrated against a standard solution of sodium thiosulphate.
2I– (aq) + H2O (l) + O3 (g)? 2OH– (a
7.18 Why does O3 act as a powerful oxidising agent?
7.18 Why does O3 act as a powerful oxidising agent?
7.18
Since ozone is not very stable at room temperature; it decomposes to give oxygen molecule and nascent oxygen on heating. The nascent oxygen, being a free radical is very reactive. Hence, it acts as a powerful oxidizing agent. The equation for the above reaction is given by,
7.17 Complete the following reactions: (i) C2H4 + O2 → (ii) 4Al + 3 O2 →
7.17 Complete the following reactions: (i) C2H4 + O2 → (ii) 4Al + 3 O2 →
7.17
(i) C2H4 + O2→ 2CO2 + 2H2O
Ethane in reaction with oxygen gives carbon dioxide and water.
(ii) 4Al + 3 O2→ 2Al2O3
Aluminium on reaction with oxygen gives alumina.
7.16 Which of the following does not react with oxygen directly? Zn, Ti, Pt, Fe.
7.16 Which of the following does not react with oxygen directly? Zn, Ti, Pt, Fe.
7.16
Pt is a noble metal (inert) and does not react with oxygen, whereas Zn, Ti, and Fe react with quickly with oxygen.
7.15
The oxygen atom has a smaller size and greater electronegativity than sulphur atom, hence intermolecular hydrogen bonding is possible in water (H2O). But, only weak Van there Waal's force holds H2S molecules, hence water is liquid and H2S is a gas.