Physics Electrostatic Potential and Capacitance

A parallel plate capacitor is charged and then charging battery is disconnected. If the plates are now pulled apart with insulated handles

Energy stored in circuit 1 is E. If capacitors in circuit 1 and circuit 2 are connected in parallel as shown, the energy stored becomes $\frac{xE}{6}$ , find x.

Potential due to electric dipole on axial position at distance r from dipole is proportional to (assume r >> length of dipole)

The force between two charged particle placed in air at separation x is F₀. Both the charged particle immerged in a medium of dielectric constant K without changing separation between two charge, then net force on one of the particle is now

Five  metallic plates each of area A and separated from adjacent plate by a distance d as shown in figure. The capacitance of the system across A and B is:

Two infinitely long parallel wires having linear charge densities λ₁ and λ₂ respectively are placed at a distance of R. The force per unit length on either wire will be

Electric  field  in  a  region  is  E = 3 ˆj N/ C . Equipotential surfaces are parallel to

Figure shows four plates each of area A and separated from another by a distance d. What is the capacitance between P and Q?

A $1\mu F$ capacitor is charged by $100V$ supply. It is then disconnected from the supply and is connected to another uncharged $1\mu F$ capacitor. The percentage of energy lost in form of heat and electromagnetic radiation is

In the diagram shown below, the block has charge $Q$ and is attached at one end of the light spring. The surface is smooth and horizontal and spring is in its natural length. If the electric field $E$ is switched on, the maximum elongation in the spring will be