Physics Electrostatic Potential and Capacitance

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New answer posted

5 months ago

0 Follower 16 Views

V
Vishal Baghel

Contributor-Level 10

Ui = ½C (V/3)² + ½C (V/3)² + ½C (2V/3)²
Uf = ½CV²
Wb = CV²/3
ΔH = [Wb - (Uf - Ui)] = CV²/6 = 0.30 mJ

New answer posted

5 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

(4/3)πR³ = 27 (4/3)πr³) ⇒ R = 3r (i)
v = Kq/r = V? /r = (q? /q? ) (r? /r? ) (i)
⇒ 220/V? = (q/ (27q) (3r/r) (i)
⇒ 220/V? = 1/9 (i)
⇒ V? = 220 * 9 = 1980 volt (i)

New answer posted

5 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

W_agent + W_battery = ΔU
W = ½ (KC - C)V² - [ (KC - C)V]V
= ½ (K - 1)CV²

New answer posted

5 months ago

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R
Raj Pandey

Contributor-Level 9

V P = V q + V - q

= K q 5 - 3 + K ( - q ) 5 + 3 * 10 2 = K q 2 - K q 8 * 10 2 = 3 K q 8 * 10 2

New answer posted

5 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Kindly go thorugh the solution

 

New answer posted

5 months ago

0 Follower 11 Views

R
Raj Pandey

Contributor-Level 9

3 μ F and 3 μ F  in parallel

 

New answer posted

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0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

5 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

For a conducting sphere, the electric field E = σ/ε? and potential V = σR/ε?
When two spheres are connected by a wire, their potentials become equal: V? = V?
σ? R? /ε? = σ? R? /ε?
σ? R? = σ? R? ⇒ σ? /σ? = R? /R?

New answer posted

5 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

C = A B ? A ? B ?

Using De-Morgan Theorem

C = A B ? A ? B ?

C = B ( A + A ? ) ? = B ?

Therefore

 

New answer posted

5 months ago

0 Follower 10 Views

A
alok kumar singh

Contributor-Level 10

Time period of satellite

T = 2 π R 3 G M

= 2 π R 3 G d 4 3 π R 3

T = 3 π G d 3 π G d = T 2

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