Physics Electrostatic Potential and Capacitance

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New answer posted

2 weeks ago

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A
alok kumar singh

Contributor-Level 10

According to relation between field and potential, we can write

E = d V d x ( i ^ ) = d ( 3 x 2 ) d x ( i ^ ) = 6 x ( i ^ )

E ( 1 , 0 , 3 ) = 6 ( i ^ ) N / C

New answer posted

2 weeks ago

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A
alok kumar singh

Contributor-Level 10

According to Law of discharging of capacitor, we can write

Q = Q 0 e t τ Q 2 8 = Q 0 e t 2 τ t 2 3 τ l n ( 2 ) , a n d

U = Q 2 2 C = Q 0 2 2 C e 2 t τ 1 2 ( Q 0 2 2 C ) = Q 0 2 2 C e 2 t τ t 1 = τ 2 l n ( 2 )

t 1 t 2 = 1 6

New question posted

2 weeks ago

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New answer posted

2 weeks ago

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V
Vishal Baghel

Contributor-Level 10

k Q e 0 . 1 2 + 1 2 m u 2 = k Q e 0 . 1 5 + 1 2 m u 2

k Q e * 0 . 0 3 0 . 1 2 * 0 . 1 5 = 1 2 m * ( v 2 u 2 )

Q = 9 . 1 * 9 9 * 1 0 1 1 1 2

= 7 5 . 0 7 5 * 1 0 1 2 4 π * ( 0 . 1 ) 2 = 5 . 9 7 n C / m 2

New answer posted

2 weeks ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

W D = Δ Q V

Δ Q = 4 μ C

Q i = 2 * 4 2 + 4 * 6 = 8 μ C

Q f = 1 2 μ C = C e q * 6

C e q = 2 μ F C 1 = C 2 = 4 μ F

k = C 1 C 0 = 2

New answer posted

3 weeks ago

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V
Vishal Baghel

Contributor-Level 10

Q 1 = C 1 V = 2 V μ C

Q 2 = Q 3 = C 2 C 3 C 2 + C 3 V = 6 * 1 2 6 + 1 2 V = 4 V μ C

Q 1 : Q 2 : Q 3 = 1 : 2 : 2

New answer posted

3 weeks ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

V = 10 ( 1 ? e ? t / R C )

2 = 20 ( 1 ? e ? t / R C )

1 1 0 = 1 ? e ? t / R C

e t / R C = 1 0 9

t R C = l n ( 1 0 9 ) = 0 . 1 0 5

C = t R * 0 . 1 0 5 = 1 0 ? 6 1 0 * 0 . 1 0 5 = 0 . 9 5 ? F

 

New answer posted

3 weeks ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

V_common = (C? V? + C? V? )/ (C? + C? )? 2 = (3? F)*12)/ (3? F)+ (3? F)*K)? 2 = 12/ (K+1)? K = 5

New answer posted

3 weeks ago

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R
Raj Pandey

Contributor-Level 9

Gain in K.E. =  Loss in P.E.

  K p = e V for proton

K α = 2 e V  for  α - particle

Again, Loss in K.E. =   Work against field

K p = e E S 0  for proton

e V = e E S 0

S 0 = V E

K α = 2 e E . S  for α -  particle

2 e V = 2 e E S

S = V E = S 0

New answer posted

3 weeks ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

tan 60° = (2kλ? /y? )/ (2kλ? /x? )


(√3λ? /x? ) = (λ? /y? ); √3λ? y? = λ? x?

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