Physics Motion in Plane

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2 months ago

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R
Raj Pandey

Contributor-Level 9

The angular acceleration direction is given along angular velocity or opposite to angular velocity depending upon whether angular velocity magnitude is increasing or decreasing and this direction remains along the axis of circular motion.

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R
Raj Pandey

Contributor-Level 9

h max   = u 2 s i n 2 ? θ 2 g = 280 * 280 2 * 9.8 * 1 4

=1000 m

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A
alok kumar singh

Contributor-Level 10

S n = Distance in n th   sec. i.e. t = n - 1 to t = n

S n + 1 = Distance in ( n + 1 ) th    sec.

i.e. t = n to t = n + 1

So as we know

S n = a 2 2 n - 1 a = acceleration

S n S n + 1 = a 2 2 n - 1 a 2 2 n + 1 - 1 = 2 n - 1 2 n + 1

S n S n + 1 = 2 n - 1 2 n + 1

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R
Raj Pandey

Contributor-Level 9

i c = s i n - 1 ? 3 4

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alok kumar singh

Contributor-Level 10

V P = V q + V - q

= K q 5 - 3 + K ( - q ) 5 + 3 * 10 2 = K q 2 - K q 8 * 10 2 = 3 K q 8 * 10 2

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A
alok kumar singh

Contributor-Level 10

Potential energy stored in the spring = 1 2 k x 2

  Now   1 2 k ( 2 ) 2 = U & 1 2 k ( 8 ) 2 = U '   (say)   U ' = 64 4 U = 16 U

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Raj Pandey

Contributor-Level 9

Angle from direction of flow = 90° + θ = 120°
⇒ θ = 30°
sin 30° = u/v ⇒ u/10 = 1/2 ⇒ u = 5 m/s

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alok kumar singh

Contributor-Level 10

The displacement S is calculated by integrating the velocity function:
S = x - x? = ∫? ¹ v dt = ∫? ¹ (v? + gt + Ft²) dt = v? + g/2 + F/3

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

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A
alok kumar singh

Contributor-Level 10

Kindly go throiugh the solution 

 

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