Physics Motion in Plane

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New answer posted

3 weeks ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

S n = Distance in n th   sec. i.e. t = n - 1 to t = n

S n + 1 = Distance in ( n + 1 ) th    sec.

i.e. t = n to t = n + 1

So as we know

S n = a 2 2 n - 1 a = acceleration

S n S n + 1 = a 2 2 n - 1 a 2 2 n + 1 - 1 = 2 n - 1 2 n + 1

S n S n + 1 = 2 n - 1 2 n + 1

New answer posted

3 weeks ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

i c = s i n - 1 ? 3 4

New answer posted

3 weeks ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

V P = V q + V - q

= K q 5 - 3 + K ( - q ) 5 + 3 * 10 2 = K q 2 - K q 8 * 10 2 = 3 K q 8 * 10 2

New answer posted

4 weeks ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

Potential energy stored in the spring = 1 2 k x 2

  Now   1 2 k ( 2 ) 2 = U & 1 2 k ( 8 ) 2 = U '   (say)   U ' = 64 4 U = 16 U

New answer posted

4 weeks ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Angle from direction of flow = 90° + θ = 120°
⇒ θ = 30°
sin 30° = u/v ⇒ u/10 = 1/2 ⇒ u = 5 m/s

New answer posted

4 weeks ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

The displacement S is calculated by integrating the velocity function:
S = x - x? = ∫? ¹ v dt = ∫? ¹ (v? + gt + Ft²) dt = v? + g/2 + F/3

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a month ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Kindly go throiugh the solution 

 

New answer posted

a month ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a month ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

U? = 5?
? = 10î + 4?
⇒ S? = U? t + ½ (? )t²
⇒ 20î + y? = (5t²)î + (5t + 2t²)?
20 = 5t² y? = 5t + 2t²
t = 2 ⇒ 18 m.

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