Physics Motion in Plane

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a month ago

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V
Vishal Baghel

Contributor-Level 10

a = ω²l = (2π/T)²l = (2π/60)²*0.1 = 1.1*10? ³ m/s²

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

580

X 1 = - 3 t 2 + 8 t + 10

v ? 1 = ( - 6 t + 8 ) i ˆ = 2 i ˆ

Y 2 = 5 - 8 t 3

v ? 2 = - 24 t 2 j ˆ

v = v ? 2 - v ? 1 = | - 24 j ˆ - 2 i ˆ |

v = 24 2 + 2 2

v = 580

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

v = 0.5t² i + 3t j + 9 k m/s ⇒ a = dv/dt = (ti + 3j) m/s²
At t=2sec,  v = 2i + 6j + 9k m/s and a = (2i + 3j) m/s²
The direction of acceleration of mosquito after 2s is given by the angle θ with the y-axis, where tanθ = a? /a? = 2/3.
So, the direction is tan? ¹ (2/3) from the y-axis.

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