Physics Motion in Plane

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New answer posted

2 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

v = 0.5t² i + 3t j + 9 k m/s ⇒ a = dv/dt = (ti + 3j) m/s²
At t=2sec,  v = 2i + 6j + 9k m/s and a = (2i + 3j) m/s²
The direction of acceleration of mosquito after 2s is given by the angle θ with the y-axis, where tanθ = a? /a? = 2/3.
So, the direction is tan? ¹ (2/3) from the y-axis.

New question posted

2 months ago

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New question posted

2 months ago

0 Follower 4 Views

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

Polygon law is applicable in both the situation given but the equation given in the reason is not useful in explaining the assertion.

New answer posted

2 months ago

0 Follower 5 Views

R
Raj Pandey

Contributor-Level 9

From triangle law of addition, we can clearly write answer.

New answer posted

3 months ago

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P
Payal Gupta

Contributor-Level 10

In elliptical orbit, areal velocity is constant

New answer posted

3 months ago

0 Follower 18 Views

V
Vishal Baghel

Contributor-Level 10

y = α x β x 2

d y d x = α 2 β x = 0

x = α 2 β

y m a x = α * α 2 β β * ( α 2 β ) 2 = α 2 4 β

Range = 2 x = α β = 2 u 2 s i n θ . c o s θ g

On comparing with

y = x tan θ - g x 2 2 u 2 c o s 2 θ

New answer posted

3 months ago

0 Follower 5 Views

P
Payal Gupta

Contributor-Level 10

F=kR3=mv2Rv=kmR2=km*1R

T=2πRv=2πRkm* (1R)TαR2

New answer posted

3 months ago

0 Follower 15 Views

P
Payal Gupta

Contributor-Level 10

If angle between them is 180° then

P*Q=q*P=0

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