Physics Motion in Plane

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V
Vishal Baghel

Contributor-Level 10

Polygon law is applicable in both the situation given but the equation given in the reason is not useful in explaining the assertion.

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a month ago

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R
Raj Pandey

Contributor-Level 9

From triangle law of addition, we can clearly write answer.

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P
Payal Gupta

Contributor-Level 10

In elliptical orbit, areal velocity is constant

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a month ago

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V
Vishal Baghel

Contributor-Level 10

y = α x β x 2

d y d x = α 2 β x = 0

x = α 2 β

y m a x = α * α 2 β β * ( α 2 β ) 2 = α 2 4 β

Range = 2 x = α β = 2 u 2 s i n θ . c o s θ g

On comparing with

y = x tan θ - g x 2 2 u 2 c o s 2 θ

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a month ago

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P
Payal Gupta

Contributor-Level 10

F=kR3=mv2Rv=kmR2=km*1R

T=2πRv=2πRkm* (1R)TαR2

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a month ago

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P
Payal Gupta

Contributor-Level 10

If angle between them is 180° then

P*Q=q*P=0

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A
alok kumar singh

Contributor-Level 10

A particle moving with uniform speed in a circular path maintains varying velocity and varying acceleration. It is because direction of both velocity as well as acceleration will change continuously.

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a month ago

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P
Payal Gupta

Contributor-Level 10

y = x5 (1 – x) = x tan θ (1xR)

tan = 5, R = 1

sinθ=526, cosθ=126

R=u2sin2θg=1

u2=26u=26m/s

y – component of initial velocity

= u sin θ

=26*526

= 5 m/s

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