Physics Ray Optics and Optical Instruments

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2 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

By conservation of angular momentum, I? ω? + I? ω? = (I? +I? )ω
ω = (I? ω? +I? ω? )/ (I? +I? ) = (0.110 + 0.25)/ (0.1+0.2) = 2/0.3 = 20/3 rad/s
K = ½ (I? +I? )ω² = ½ (0.3) (20/3)² = 20/3 J.

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution 

 

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

δ_min = (µ - 1)A
= (1.5 - 1)1
= 0.5
δ_min = 5/10
N=5

New answer posted

2 months ago

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R
Raj Pandey

Contributor-Level 9

1 f = ( μ - 1 ) 1 R 1 - 1 R 2

R 1 =

R 2 = - 30 c m

1 f = ( 1.5 - 1 ) 1 - 1 - 30

1 f = 0.5 30 f = 60 c m

New answer posted

2 months ago

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R
Raj Pandey

Contributor-Level 9

m = f o f e 5 = f o f e

f o = 5 f e f o + f e = 60

6 f e = 60 f e = 10

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

Case-I:

If final image is at least distance of clear vision

M.P. = L f 0 1 + D f e ; 375 = 150 5 1 + 25 f e

375 30 = 1 + 25 f e ; 345 30 = 25 f e

f e = 750 345 = 2.17 c m ; f e 22 m m

Case-II:

In final image is at infinity

M.P. = L f 0 D f e = 375 f e = 22 m m

 

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

  1 f = μ g - 1 1 R 1 - 1 R 2

1 f l = μ g μ l - 1 1 R 1 - 1 R 2

(i) f l f = μ g - 1 μ g μ l - 1 = 1.5 - 1 1.5 1.41 - 1 = 8.875 9 .

New answer posted

2 months ago

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R
Raj Pandey

Contributor-Level 9

V = 1 μ ε n = μ r ε r = 2

s i n ? c = 1 2 c = 30 ?

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