Physics Ray Optics and Optical Instruments

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New answer posted

5 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

Light rays travel undeviated if the refractive index of the medium does not change for any value of angle of incidence.
i.e. n? = n?
1.2 + 10.8*10? ¹? /λ² = 1.45 + 1.8*10? ¹? /λ²
9.0*10? ¹? /λ² = 0.25
λ² = 36*10? ¹?
λ = 6*10? m = 600 nm

New answer posted

5 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

μ = sin (A + δm)/2) / sin (A/2)
Since, δm = A
μ = sin (A) / sin (A/2) = (2sin (A/2)cos (A/2) / sin (A/2)
μ = 2cos (A/2

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

By shell's law
(sin θ)/ (sin θ') = 4/3 . (i)
For TIR on second surface
sin θ' > sin θc
(θ' + θ' = 90)
sin (90 - θ') > sin θc
cos θ' > sin θc
1 - sin²θ' > sin²θc (By equation (i) )
1 - (3/4 sin θ)² > sin²θc
[sin θc = 3/4]
1 - (9/16)sin²θ > (9/16)
1 - 9/16 > (9/16)sin²θ
7/16 > (9/16)sin²θ
sinθ < 7/3

New answer posted

5 months ago

0 Follower 10 Views

R
Raj Pandey

Contributor-Level 9

μ? sin 30° = μ? sin θ

⇒ 2.42 * (1/2) = (1) sinθ
sinθ = 1.21 > 1
Refraction is not possible, total internal reflection

 

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

Focus of a spherical convex mirror is in the same side of centre of curvature. Thus, f = + 1 2 r .

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

Maximum Distance = 3 (x + x) = 6x = 3 * 2x = 3 * 50 = 150 cm

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New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

r ^ i ^ = 2 c o s θ n ^ . . . . . . ( 1 )

i ^ . n ^ = c o s θ . . . . . . ( 2 )

r ^ = i ^ 2 ( i ^ . n ^ ) n ^

b = a 2 ( a . c ) c

New answer posted

5 months ago

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P
Payal Gupta

Contributor-Level 10

As height of image is less than height of image and has same orientation as that of object, so mirror must be convex.

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

f0=140 cm and fe=5 cm

For distant object,

m = f 0 f e = 1 4 0 5 = 2 8

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