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New answer posted
2 months agoContributor-Level 10
E ∝ F? A? T?
[M¹L²T? ²] ∝ [M¹L¹T? ²]? [LT? ²]? [T]?
a = 1
a + b = 2 ⇒ b = 1
-2a - 2b + c = -2
⇒ c = 2
a = 1 b = 1 c = 2
E ∝ [F] [A] [T²]
New answer posted
2 months agoContributor-Level 10
hc/λ = K? + φ [given φ is negligible]
So, hc/λ = K?
λ? = h/√ (2mK? ²) ⇒ K? = h²/ (2mλ? ²)
(hc)/λ = h²/ (2mλ? ²) ⇒ λ = (2mc/h)λ? ²
New answer posted
2 months agoContributor-Level 10
Least count = 1 mm / 100 = 0.01 mm
Diameter = main scale reading + circular scale reading
Diameter = 0 + 52 * 0.01 mm
= 0.52 mm = 0.052 cm
New answer posted
2 months agoContributor-Level 9
Theory based
Capacitor in parallel removes the AC ripple from the rectified output.
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