Physics

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New answer posted

a year ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

α = Δ l C Δ l E = 3 . 5 4 = 7 8

β = α 1 − α = 7 / 8 1 − 7 / 8 = 7

New answer posted

a year ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Focus of a spherical convex mirror is in the same side of centre of curvature. Thus, f = + 1 2 r .

New answer posted

a year ago

0 Follower 17 Views

R
Raj Pandey

Contributor-Level 9

H = λ 4

⇒ 2 0 = λ 4

λ = 8 0 c m

Now first overtone for open organ pipe

L 2 = 4 λ 4 = λ = 8 0     c m

 

New answer posted

a year ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

In isothermal process, temperature is constant.

In isochoric process, volume is constant.

In adiabatic process, there is no exchange of heat.

In isobaric process, pressure is constant.

New answer posted

a year ago

0 Follower 7 Views

R
Raj Pandey

Contributor-Level 9

Q 1 = 2 0 ° C w a t e r → 1 0 0 °     s t e a m

Q 1 = m c Δ T + m L

= m [ c Δ T + L ]

= 3 1 0 0 0 = 3 1 * 1 0 3 c a l

Q 2 = 2 9 3 3 7 3 * 3 1 * 1 0 3

 

 

New answer posted

a year ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

For part AM, slope of v – t graph is constant but negative. For part MB, slope of v – t graph is constant but positive.

New answer posted

a year ago

0 Follower 6 Views

R
Raj Pandey

Contributor-Level 9

τ = η v h  

              Given

              τ = 1 0 − 3 N / m 2  

              (shear stress)

              h =?

              v = 36 km/hr = 10 m/sec

              1 0 − 3 = 1 0 − 2 * 1 0 h

h = 100 m

New answer posted

a year ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

γ = 3 α

Δ V = γ V Δ T = 3 α . a 3 . Δ T

New answer posted

a year ago

0 Follower 14 Views

A
alok kumar singh

Contributor-Level 10

If charge (-Q) at origin is replaced by (+Q), then electric field at the centre of the cube is zero. Thus, electric field at the centre of the cube is as if only (-2Q) charge is present at the origin.

E → = 1 4 π ε 0 ( − 2 Q ) ( 3 2 a ) 2 . 1 3 ( x ^ + y ^ + z ^ ) = | − 2 Q 3 3 π ε 0 a 2 ( x ^ + y ^ + z ^ )

New answer posted

a year ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

F 1 c o s 4 5 ° + F 2 c o s 4 5 ° + F 3 = m v 2 r

⇒ G m 2 ( 2 r ) 2 . 1 2 + G m 2 ( 2 r ) 2 . 1 2 + G m 2 ( 2 r ) 2 = m v 2 r  

  ⇒ v = G m 4 r ( 2 2 + 1 )            

Putting m = 1 kg and r = 1 m,

v = 1 2 G ( 1 + 2 2 )            

 

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