Physics
Get insights from 5.6k questions on Physics, answered by students, alumni, and experts. You may also ask and answer any question you like about Physics
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
2 months agoContributor-Level 10
velocity of car at t = 4sec is
v = u + at
v = 0 + 5 (4)
= 20 m/s
At t = 6sec
acceleration is due to gravity ∴ a = g = 10 m/s
v? = 20 m/s (due to car)
v? = u + at
= 0 + g (2) (downward)
= 20 m/s (downward)
v = √ (v? ² + v? ²)
= √ (20² + 20²)
= 20√2 m/s
New answer posted
2 months agoContributor-Level 10
i = (V? /R) (1 - e? /? )
U = ½Li²
dU/dt = Li (di/dt)
(R/2L) * (V? ²/R²) (1 - e? /? )²e? /? = (V? ²/R) (1 - e? /? )
t = (L/R)ln2
New answer posted
2 months agoContributor-Level 10
(4/3)πR³ = 27 (4/3)πr³) ⇒ R = 3r (i)
v = Kq/r = V? /r = (q? /q? ) (r? /r? ) (i)
⇒ 220/V? = (q/ (27q) (3r/r) (i)
⇒ 220/V? = 1/9 (i)
⇒ V? = 220 * 9 = 1980 volt (i)
New answer posted
2 months agoNew answer posted
2 months agoNew answer posted
2 months agoContributor-Level 10
W_agent + W_battery = ΔU
W = ½ (KC - C)V² - [ (KC - C)V]V
= ½ (K - 1)CV²
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 679k Reviews
- 1800k Answers








