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New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

7 months ago

0 Follower 14 Views

A
alok kumar singh

Contributor-Level 10

Power delivered = 1000 W
Voltage = 220 V
Transmission 'I' = 1000/220
Power loss = I²R
Efficiency = (1000x100)/ (1000 + I²R)

New answer posted

7 months ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

ln |R| = ln|R? | - λt
and T? /? ∝ 1/λ
where 'N' is slope
V² = 2gh
h = √2gh
h = -√2gh + gt²/2
gt² - 2√2ght - 2h = 0
t = (2√2gh ± √ (8gh + 8gh)/2g
t = (2√2gh + 4√gh)/2g as cannot be negative.
∴ t = (2 + √2)√ (h/g) → 3.4√ (h/g)
T? /? (A):T? /? (B):T? /? (C) = 10/6 : 5/6 : 5/2 = 2:1:3

New answer posted

7 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

7 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

B? = µ? I/ (2π (r)
|τ| = |I * l x F|
τ = 2aF
τ = 2 (a) (I) (2a) (µ? I/2πb)
τ = 2µ? I²a²/πb
B on the also equal to B? as
B = µ? I/ (2π√ (b² + a²/4) + µ? I/4
b >>> a
disp = ( kg/ms ²) (s) (m³/kg)
disp = (1) (16) (1/300) (1/1000)
disp in mm = 1000/ (300x100) = 0.03333
⇒ 3/100

New answer posted

7 months ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

7 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

Use the equation to find ' N ':
P = 2/3 (v) (N/V) (1/2 mu²)

New answer posted

7 months ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

7 months ago

0 Follower 12 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

7 months ago

0 Follower 14 Views

A
alok kumar singh

Contributor-Level 10

V = I? (G + R? )
1 = I? (G + R? )
2 = I? (G + R? + R? )
2 = 1 + I? R?
I? R? = 1
R? = G + R?

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