Physics

Physics Work, Energy and Power

Contributor-Level 9

According to principle of equi-partition of Energy, the average energy per molecules associated with each degree of freedom is (1/2)kT.

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10 months ago

A constant power delivering machine has towed a box, which was initially at rest, along a horizontal straight line. The distance moved by the box in time 't' is proportional to:

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Contributor-Level 9

m (dv/dt) = P ⇒ ∫v dv = ∫ (P/m) dt ⇒ v = (2Pt/m)¹/²
⇒ ∫dx = ∫ (2P/m)¹/² t¹/² dt ⇒ x = (2P/m)¹/² (2/3)t³/² ⇒ x ∝ t³/²

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10 months ago

A carrier signal C(t) = 25 sin(2.512 * 10¹⁰t) is amplitude modulated by a message signal m(t) = 5 sin(1.57 * 10⁸t) and transmitted through an antenna. What will be the bandwidth of the modulated signal?

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Physics Physics Ncert Solutions Class 12th

Contributor-Level 10

Frequency of message signal, f? = (1.57 * 10? ) / (2 * 3.14) = 2.5 * 10? Hz
Bandwidth = 2f? = 5 * 10? Hz = 50MHz

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10 months ago

Your friend is having eye sight problem. She is not able to see clearly a distant uniform window mesh and it appears to her non-uniform and distorted. The doctor diagnosed the problems as:

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Contributor-Level 9

An eye with defect of myopia can not see distant objects clearly, while that of astigmatism sees objects non-uniform and distorted.

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10 months ago

A hairpin like shape as shown in figure is made by bending a long current carrying wire. What is the magnitude of a magnetic field at point P which lies on the centre of the semicircle?

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Physics Work, Energy and Power

Contributor-Level 10

The magnetic field B is calculated as:
B = 2 * (μ? I / 4πr) + (μ? I / 4πr) = (μ? I / 4πr) * (2 + π)

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10 months ago

A rubber ball is released from a height of 5 m above the floor. It bounces back repeatedly, always rising to 81/100 of the height through which it falls. Find the average speed of the ball. (Take g = 10 ms⁻²)

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Contributor-Level 10

For a bouncing object with initial height h = 5m and coefficient of restitution e = 0.9 (so e² =0.81):
Total distance traveled, d = h + 2e²h + 2e? h + . = h * (1 + e²) / (1 - e²)
Total time taken, t = √* (2h/g)* + 2√* (2e²h/g)* + 2√* (2e? h/g)* + . = √* (2h/g)* * (1 + e) / (1 - e)
Average speed = d/t = √* (gh/2)* * (1 + e²) / (1 + e)² = 5 * (1.81) / (1.9)² = 2.50 m/s

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10 months ago

Physics Class 11th

A thin circular ring of mass M and radius r is rotating about its axis with an angular speed ω. Two particles having mass m each are now attached at diametrically opposite points. The angular speed of the ring will become:

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Contributor-Level 9

Using conservation of Angular momentum along axis of rotation, we can write
Mr²ω = (Mr² + 2mr²)ω? ⇒ ω? = Mω / (M + 2m)

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10 months ago

Two identical photo-cathodes receive the light of frequencies f? and f? respectively. If the velocities of the photo-electrons coming out are v? and v? respectively, then

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Contributor-Level 10

The equation representing the photoelectric effect is given as:
(1/2)mv? ² = hf? - φ . (1)

This continues the solution from number 6 on the previous page.
(1/2)mv? ² = hf? - φ . (2)
With the help of equations (1) and (2), we can write:
v? ² - v? ² = (2h/m) (f? - f? )

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10 months ago

What happens to the inductive reactance and the current in a purely inductive circuit if the frequency is halved?

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Physics Physics Motion in Plane

Contributor-Level 10

Given the initial relationships:
X? = ωL and i? = V? / (ωL)
If the angular frequency ω is halved, the inductive reactance X? is halved, while the peak current i? is doubled.

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10 months ago

The velocity of a particle is v = v₀ + gt + Ft². Its position is x = 0 at t = 0; then its displacement after time (t = 1) is:

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