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New answer posted

7 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

K = U

½ mω² (A² - x²) = ½ mω²x²

A² - x² = x²

A² = 2x²

x = ± A/√2

New answer posted

7 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

P? - P? = 4T/a

P? - P? = 4T/b

P? - P? = 4T (1/a - 1/b)

Also, P? - P? = 4T/r

4T/r = 4T (1/a - 1/b)

1/r = (b-a)/ab

r = ab / (b-a)

New answer posted

7 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

η = 1 - T_C / T_H

η = 1 - 400/800 = 1 - ½ = ½

η = W/Q_H ⇒ ½ = W/Q_H ⇒ Q_H = 2W = 2 * 1200 = 2400 J

New answer posted

7 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

B = μni

B = (500 * 4π * 10? ) * 1000 * 5

B = π Tesla

New answer posted

7 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

f = f_Translational + f_Rotational + f_Vibrational

f = 3 + 3 + 48 = 54 (Since each vibrational mode has two degrees of freedom)

γ = 1 + 2/f = 1 + 2/54 = 1 + 1/27 = 28/27 ≈ 1.03

New answer posted

7 months ago

0 Follower 7 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

7 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

N = mg - F_L

f_s = mv²/R ≤ μsN = μs (mg - F_L)

F_L = m (v²/μsR - g)

New answer posted

7 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

E_ground (H-atom) = -13.6 eV

E_carbon = E_ground (H-atom) * Z²/n²
For carbon, Z=6.

-13.6 eV = -13.6 eV * (6²/n²)

1 = 36/n²

n² = 36

n = 6

New answer posted

7 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

7 months ago

0 Follower 9 Views

V
Vishal Baghel

Contributor-Level 10

K? = ½ mv² + ½ Iω²
Since I =? mr² and v=rω,
K? = ½ mv² + ½ (? mr²) (v/r)² = ½ mv² +? mv² = (7/10)mv² = 140 J

K_f = 0.05 K?
(7/10)mv_f² = 0.05 * (140)
(7/10)mv_f² = 7
v_f² = 20
v_f = √20 ≈ 4.47 m/s

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