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New answer posted
4 months agoContributor-Level 10
We know, P = √2Em and λ = h/√2Em
For 1st maxima, 2nd sinθ = λ
Put (1) and get the answer
E = 50.47eV.
B = µ? I (200)/2R? R? = 20 cm; R? = 1 cm
e = -dΦ/dt = π (R? )² (500) dB/dt
= π (R? )² (500) (µ? I/2R? ²) (200) (10t-2)
= π (1/10000) (500) (200) (µ? ) (8) (5)/ (2)
= 16π² x 10 x 5 x 10?
= 800π² x 10?
e = 0.7887mv
4/x = 0.8; x = 5.
New answer posted
4 months agoContributor-Level 10
M? = 200MeV/C², m = 1Gev/C²
Initial velocity of particle is 'V'.
Final velocity of hydrogen atom is 'V'
M? V? = mV
V = M? V? /m
Also, 1/2 M? V? ² = 1/2 mV² + 3/4 x 13.6
Put (1) and get answer
1/2 M? V? ² = 51/4 eV
Hence, N = 51.
New answer posted
4 months agoContributor-Level 10
F = (i + 2j + 3k)N
r = (4 - 1)i + (3 - 2)j + (-1 - 1)k)
τ = r x F
= (3i + j - 2k) x (i + 2j + 3k)
ijk
3 1 -2 ⇒ I (3 + 4) - j (11) + (6-1)k
1 3
7i - 11j + 5k
|τ| = √121 + 25 + 49
|τ| = √195 ; x = 195
New answer posted
4 months agoContributor-Level 10
Power delivered = 1000 W
Voltage = 220 V
Transmission 'I' = 1000/220
Power loss = I²R
Efficiency = (1000x100)/ (1000 + I²R)
New answer posted
4 months agoContributor-Level 10
ln |R| = ln|R? | - λt
and T? /? ∝ 1/λ
where 'N' is slope
V² = 2gh
h = √2gh
h = -√2gh + gt²/2
gt² - 2√2ght - 2h = 0
t = (2√2gh ± √ (8gh + 8gh)/2g
t = (2√2gh + 4√gh)/2g as cannot be negative.
∴ t = (2 + √2)√ (h/g) → 3.4√ (h/g)
T? /? (A):T? /? (B):T? /? (C) = 10/6 : 5/6 : 5/2 = 2:1:3
New answer posted
4 months agoContributor-Level 10
B? = µ? I/ (2π (r)
|τ| = |I * l x F|
τ = 2aF
τ = 2 (a) (I) (2a) (µ? I/2πb)
τ = 2µ? I²a²/πb
B on the also equal to B? as
B = µ? I/ (2π√ (b² + a²/4) + µ? I/4
b >>> a
disp = ( kg/ms ²) (s) (m³/kg)
disp = (1) (16) (1/300) (1/1000)
disp in mm = 1000/ (300x100) = 0.03333
⇒ 3/100
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