Physics
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New answer posted
a year agoContributor-Level 10
Frequency of message signal, f? = (1.57 * 10? ) / (2 * 3.14) = 2.5 * 10? Hz
Bandwidth = 2f? = 5 * 10? Hz = 50MHz
New answer posted
a year agoContributor-Level 9
An eye with defect of myopia can not see distant objects clearly, while that of astigmatism sees objects non-uniform and distorted.
New answer posted
a year ago
Contributor-Level 10
The magnetic field B is calculated as:
B = 2 * (μ? I / 4πr) + (μ? I / 4πr) = (μ? I / 4πr) * (2 + π)
New answer posted
a year agoContributor-Level 10
For a bouncing object with initial height h = 5m and coefficient of restitution e = 0.9 (so e² =0.81):
Total distance traveled, d = h + 2e²h + 2e? h + . = h * (1 + e²) / (1 - e²)
Total time taken, t = √* (2h/g)* + 2√* (2e²h/g)* + 2√* (2e? h/g)* + . = √* (2h/g)* * (1 + e) / (1 - e)
Average speed = d/t = √* (gh/2)* * (1 + e²) / (1 + e)² = 5 * (1.81) / (1.9)² = 2.50 m/s
New answer posted
a year agoContributor-Level 9
Using conservation of Angular momentum along axis of rotation, we can write
Mr²ω = (Mr² + 2mr²)ω? ⇒ ω? = Mω / (M + 2m)
New answer posted
a year agoContributor-Level 10
The equation representing the photoelectric effect is given as:
(1/2)mv? ² = hf? - φ . (1)
This continues the solution from number 6 on the previous page.
(1/2)mv? ² = hf? - φ . (2)
With the help of equations (1) and (2), we can write:
v? ² - v? ² = (2h/m) (f? - f? )
New answer posted
a year agoContributor-Level 10
Given the initial relationships:
X? = ωL and i? = V? / (ωL)
If the angular frequency ω is halved, the inductive reactance X? is halved, while the peak current i? is doubled.
New answer posted
a year agoContributor-Level 10
The displacement S is calculated by integrating the velocity function:
S = x - x? = ∫? ¹ v dt = ∫? ¹ (v? + gt + Ft²) dt = v? + g/2 + F/3
New answer posted
a year ago
Contributor-Level 10
The acceleration 'a' is calculated as:
a = (g sinθ) / (1 + I/mr²) = (10 * sin30°) / (1 + 2/5) = 25/7 m/s²
The time 't' is calculated as:
t = 2v / a = (2 * 1) / (25/7) = 0.57 s
New answer posted
a year ago
Contributor-Level 10
For an elastic collision where C comes to rest, and the compression in the spring is maximum, the velocities of A and B are equal (v). Using the conservation of mechanical energy:
(1/2)mv? ² = 2 * (1/2)mv² + (1/2)kx²
This gives the maximum compression x as:
x = v? * √* (m / 2k)*
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