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New answer posted

7 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

dW? = Eqdx
∫ dU? = ∫ kQ/x² dxq
W? = kQq (-1/x)|? ^ (R+y)
W? = kQq (y)/ (R) (R + y)
W? + W? = 1/2 mv²
V² = 2/m (kQqy/ (R) (R+y) + mgy)
V² = 2y (kQq/ (m (R) (R+y) + g) ; k = 1/ (4πε? )

New answer posted

7 months ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

1/4 m (210)² = m (0.03) x (4.2) x 1000 x ΔT ; Q = mSΔt
ΔT = (210) (210)/ (4) (4.2) (0.03) (1000) = 87.5°C

New answer posted

7 months ago

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A
alok kumar singh

Contributor-Level 10

Photodiode operate in reverse bias. The photocurrent increases initially and saturates fi

New answer posted

7 months ago

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A
alok kumar singh

Contributor-Level 10

f = V (n)/ (4 (1 - 17/100) (as closed from end)
f = (n - 2) (v)/ (4 (1 - 24.5/100)
nV (100)/4 (83) = (n - 2) (v) (100)/ (4) (75.5)
75.5n = 83 (n - 2)
75.5n = 83 (M - 2)
7.5n = 166
n = 22 (approx)
f = (330) (22) (100)/ (4 (83) = 2200 Hz

New answer posted

7 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

As Torque net = 0
Hence, L = constant
Iω = (3I + I)ω'
ω' = ω/4
Loss in K.E. = 1/2 Iω² - 1/2 (I + 3I)ω²/16 = 1/2 Iω² (1 - 1/4)
Fractional loss = (3/4 * 1/2 Iω²)/ (1/2 Iω²) = 3/4

New answer posted

7 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Kindly go throiugh the solution 

 

New answer posted

7 months ago

0 Follower 8 Views

A
alok kumar singh

Contributor-Level 10

As it just floats B = mg
(4πR³/3) (ρ‎? ) (g) = (4πR³/3 - 4πr³/3) (ρ‎? ) (g)
R³ = (R³ - r³) (27/8)
On solving we get,
r = 8/9 R (approx)

New answer posted

7 months ago

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J
Jaya Sharma

Contributor-Level 10

Refractive index (n) is a dimensionless quantity that has no units. Since both numerator and denominator are in meters per seconds (m/s), both units cancel each other. This makes refractive index simply a number. 

New answer posted

7 months ago

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J
Jaya Sharma

Contributor-Level 10

Absolute refractive index is the ratio of speed of light in air/vacuum to speed of light in any medium. It is closely related to refractive index, except that it is relative to vacuum and not to any other medium. This is different from relative refractive index because it is the ratio of speed of light in one medium compared to the speed of light in another medium.

New answer posted

7 months ago

0 Follower 4 Views

J
Jaya Sharma

Contributor-Level 10

This type of refraction is the bending of light rays when they pass through the atmosphere of Earth because of the change in the air density. The density of air varies with pressure and temperature. 

Due to the atmospheric refraction, celestial objects appear higher than they actually are. This leads to an advanced sunrise and a delayed sunset as well as the twinkling of stars.

When light from space enters the Earth's atmosphere, it slows down and changes direction as light moves from a rarer to a denser medium, which causes refraction.

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