Physics
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New answer posted
4 months agoContributor-Level 10
R_eq = R? + R?
L_total / (K_eq * A) = L? / (K? A) + L? / (K? A)
Assuming L? = L? = l, L_total = 2l
2l / (K_eq * A) = l/ (K? A) + l/ (K? A)
2/K_eq = 1/K? + 1/K? = (K? + K? )/ (K? )
K_eq = 2K? K? / (K? + K? )
New answer posted
4 months agoContributor-Level 10
U = U? + U? = (n? /N_A) (F? R/2)T? + (n? /N_A) (F? R/2)T?
For the mixture: U = (n? +n? )/N_A * (FR/2)T
F = (n? F? + n? F? ) / (n? + n? )
Equating the expressions for U and solving for T gives:
T = (n? F? T? + n? F? T? ) / (n? F? + n? F? )
New answer posted
4 months agoContributor-Level 10
I = I? sin (ωt) + I? cos (ωt)
This can be written as I = I? sin (ωt + φ), where I? = √ (I? ² + I? ²)
A hot wire ammeter reads the rms value of the current.
I_rms = I? /√2 = √ (I? ² + I? ²)/√2
New answer posted
4 months agoContributor-Level 10
P? - P? = 4T/a
P? - P? = 4T/b
P? - P? = 4T (1/a - 1/b)
Also, P? - P? = 4T/r
4T/r = 4T (1/a - 1/b)
1/r = (b-a)/ab
r = ab / (b-a)
New answer posted
4 months agoContributor-Level 10
η = 1 - T_C / T_H
η = 1 - 400/800 = 1 - ½ = ½
η = W/Q_H ⇒ ½ = W/Q_H ⇒ Q_H = 2W = 2 * 1200 = 2400 J
New answer posted
4 months agoContributor-Level 10
f = f_Translational + f_Rotational + f_Vibrational
f = 3 + 3 + 48 = 54 (Since each vibrational mode has two degrees of freedom)
γ = 1 + 2/f = 1 + 2/54 = 1 + 1/27 = 28/27 ≈ 1.03
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