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New answer posted
7 months agoContributor-Level 10
The circuit diagram represents an XOR Gate. The output Y is derived as:
Y = (A? B? ) (A + B) = (A? + B? ) (A + B) = A? B + AB? (XOR Gate)
New answer posted
7 months agoContributor-Level 9
Layers of atmosphere are in order of (from bottom) troposphere, stratosphere, mesosphere, thermosphere.
New answer posted
7 months agoContributor-Level 9
Fringe width, β = (λD) / d = (5890 * 10? ¹? * 0.5) / (0.5 * 10? ³) = 589 * 10? m
Distance between first and third bright fringe = 2β = 1178 * 10? m.
New answer posted
7 months agoContributor-Level 9
For adiabatic process CD,
W = (P? V? - P? V? ) / (γ - 1) = (100 * 4 - 200 * 3) / (1.4 - 1) = -500J
New answer posted
7 months agoContributor-Level 9
qE = mg ⇒ neE = (4/3)πr³ρg
⇒ n = (4πr³ρg) / (3eE) = (4 * 3.14 * (2 * 10? ³ )³ * 3 * 10³ * 9.81) / (3 * 1.6 * 10? ¹? * 3.55 * 10? ) = 1.73 * 10¹?
New question posted
7 months agoNew answer posted
7 months agoContributor-Level 10
For series combination: s = R? + R?
For parallel combination: p = (R? ) / (R? + R? )
Given the condition s = np:
R? + R? = n * (R? ) / (R? + R? )
(R? + R? )² = nR? R?
R? ² + 2R? R? + R? ² = nR? R?
R? ² - 2R? R? + R? ² + 4R? R? = nR? R?
(R? - R? )² = (n - 4)R?
(R? - R? )² / (R? ) = n - 4
n = 4 + (R? - R? )² / (R? )
Since (R? - R? )² is always non-negative, the minimum value of the term (R? - R? )² / (R? ) is 0. This occurs when R? = R?
Therefore, the minimum value of n is 4.
New answer posted
7 months agoContributor-Level 10
For the combined system of mass M and m, the acceleration under an applied force F is:
a = F / (M + m)
The static friction force (f_s) on the top block (m) provides its acceleration:
f_s = MA = m * [F / (M + m)] = mF / (M + m)
For the top block not to slip, the required static friction must be less than or equal to the maximum possible static friction (μmg):
f_s ≤ μmg
mF / (M + m) ≤ μmg
F ≤ μ (M + m)g
Using the values implied in the solution:
F ≤ 21 N
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