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New answer posted

6 months ago

0 Follower 5 Views

V
Vishal Baghel

Contributor-Level 10

r 1 = 2 i ^ + 4 j ^ 2 k ^ , r 2 = i ^ + 2 j ^ + α k ^

Projection of r 1  on r 2  is zero r 1 . r 2  = 0

2 + 8 - 2 = 0=> α= 5

New answer posted

6 months ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

F=10i^+5j^

a=10mi^+5mj^

=100.1kgi^+50.1j^

a=100i^+50j^

ax=100, ay=50

Sx=ut+12at2

=0*2+12*100*2*2

Sx = 200 m

ab=200100=2

New answer posted

6 months ago

0 Follower 6 Views

P
Payal Gupta

Contributor-Level 10

Given, L = 2H

l = 2 sin (t2)

u = 0 2 L i d i = L 2 [ i 2 ] 0 2 = L 2 [ 4 0 ]

u = 2 2 * 4 = 4 J

New answer posted

6 months ago

0 Follower 9 Views

P
Payal Gupta

Contributor-Level 10

R e q = 2 . 5 Ω

l = v R e q = 5 2 . 5 = 2 A

New answer posted

6 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

 H=I2Rt=22*R*15

300=60R

R=5Ω

Now for 3A, time = 10 sec

H'=l2Rt=32*5*10=450J

New answer posted

6 months ago

0 Follower 8 Views

P
Payal Gupta

Contributor-Level 10

2 4 * 8 3 2 = 6 μ F

New answer posted

6 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

H=λ4

20=λ4

λ=80cm

Now first overtone for open organ pipe

L2=4λ4=λ=80cm

New answer posted

6 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

Q1=20°Cwater100°steam

Q1=mcΔT+mL

=m [cΔT+L]

=31000=31*103cal

Q2=293373*31*103

= 2 4 . 3 5 * 1 0 3 c a l

New answer posted

6 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

τ=ηvh

Given

τ=103N/m2

(shear stress)

h =?

v = 36 km/hr = 10 m/sec

103=102*10h

h = 100 m

New answer posted

6 months ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

by conservation of mechanical energy

K.Ei + P.Ei = K.Ef + P.Ef

12*0.5v2+0=12*0.5 (v2)2+12kx2

12*0.5 [v2v24]=12kx2

1.5412*12=k*9100

1.5*369*100=k

k = 600 N/m1

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