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9 months ago

Physics Moving Charges and Magnetism

A deuteron and a proton moving with equal kinetic energy enter into to a uniform magnetic field at right angle to the field. If r_d and r_p are the radii of their circular paths respectively, then the ratio $\frac{r_{d}}{r_{p}}$ will be $\sqrt[]{x} : 1$ where x is……….

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Payal Gupta

Contributor-Level 10

r_d = (Radius of deuteron)

$= \frac{m_{d} v_{d}}{q_{d} B}$

$= \frac{\sqrt[]{2 m_{d} k . E}}{q_{d} B}$

$= \frac{\sqrt[]{2 m_{P}}}{\sqrt[]{m_{P}}} * \frac{q_{P}}{q_{d}}$ $[q_{P} = q_{d} = 1.6 * 1 0_{C}^{- 19}]$

$= \sqrt[]{2} : 1$

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New answer posted

9 months ago

Physics Semiconductors

Identify the operation performed by the circuit given below:

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

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New answer posted

9 months ago

Physics Electrostatic Potential and Capacitance

A parallel plate capacitor is made up of stair like structure with a plate area A of each stair and that is connected with a wire of length b, as shown in the figure. The capacitance of the arrangement is $\frac{x}{15} \frac{\in_{0} A}{b},$ the value of x is……………

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Payal Gupta

Contributor-Level 10

$C_{1} = \frac{\in_{0} A}{5 b}$

$C_{2} = \frac{\in_{0} A}{3 b}$

$C_{3} = \frac{\in_{0} A}{b}$

$C_{e q} = C_{1} + C_{2} + C_{3}$

$= \frac{\in_{0} A}{b} [\frac{1}{5} + \frac{1}{3} + 1]$

$C_{e q} = \frac{23}{15} \frac{\in_{0} A}{b}$

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New answer posted

9 months ago

Physics Oscillations

A particle executives simple harmonic motion. Its amplitude is 8cm and time period is 6s. The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is………… s.

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Payal Gupta

Contributor-Level 10

A = 8 cm

T = 6 sec

q = 60° from A to B

During reaching the point its maximum amplitude from point (A)

$θ = 60 ° = \frac{π^{C}}{3}$

$θ = ω t$

$\frac{π}{3} = \frac{2 π}{6} t$

t = 1 sec

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New answer posted

9 months ago

Physics Thermodynamics

A diatomic gas $(γ = 1.4)$ does 400 J of work when it is expanded isobarically. The heat given to the gas in the process is…………….J.

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Payal Gupta

Contributor-Level 10

$w = P Δ v = n R Δ T = 400 J$ - (1)

$Q = n C_{P} Δ T = \frac{n R y}{y - 1} Δ T$

$Q = \frac{14}{4} * 400$

Q = 1400 J

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New answer posted

9 months ago

Physics System of Particles and Rotational Motion

A rolling wheel of 12kg is on an inclined plane at position P and connected to a mass of 3kg through a string of fixed length and pulley as shown in figure.

Consider PR as friction free surface. The velocity of centre of mass of the wheel when it reaches at the bottom Q of the inclined plane PQ will be $\frac{1}{2} \sqrt[]{x g h} m / s .$ The value of x is…………

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Payal Gupta

Contributor-Level 10

By conservation of Energy

$m g h = \frac{1}{2} l_{P} ω^{2}$

3gh $= \frac{1}{2} (M R^{2} + M R^{2}) ω^{2}$

$3 g h = m v^{2}$

$v^{2} = \frac{3 g h}{12}$

$v = \frac{\sqrt[]{g h}}{2} = \frac{\sqrt[]{x g h}}{2}$

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9 months ago

Physics Laws of Motion

A mass of 10kg is suspended vertically by a rope of length 5m from the roof. A force of 30 N is applied at the middle point of rope in horizontal direction. The angle made by upper half of the rope with vertical is q = tan^-¹ (x * 10^-¹). The value of x is…………….

(Given, g = 10 m/s²)

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Payal Gupta

Contributor-Level 10

F.B.D. of point 'P'

$T s i n θ = 30$ - (1)

$T c o s θ = 100$ - (2)

$(1) \div (2)$

$t a n θ = \frac{3}{10} \Rightarrow θ = t a n^{- 1} (3 * 1 0^{- 1})$

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New answer posted

9 months ago

Physics Communication Systems

We do not transmit low frequency signal to long distances because-

(A) The size of the antenna should be comparable to signal wavelength which is unreal

(B) Effective power radiated by a long wavelength baseband signal would be high.

(C) We want to avoid mixing up signals transmitted by different transmitter simultaneously.

(D) Low frequency signal can be sent to log distances by superimposing with a high frequency wave as well.

Therefore, the most suitable options will be

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Payal Gupta

Contributor-Level 10

For high wavelength, size of antenna should be high.

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New answer posted

9 months ago

Physics Semiconductor Electronics

For a transistor to act as a switch, it must be operated in

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Payal Gupta

Contributor-Level 10

For Transistor

to act as a switch → Saturation & cut – off state

to act as an amplifier → Active Region

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New answer posted

9 months ago

Physics Atoms

Given below are two statements:

Statement I : In hydrogen atom, the frequency of radiation emitted when an electron jumps from lower energy orbit (E₁) to higher energy orbit (E₂), is given as hf = E₁ = E₂

Statement II : The jumping of electron from higher energy orbit (E₂) to lower energy orbit (E₁) is associated with frequency of radiation given as f = (E₂ – E₁) / h

This condition is Bohr's frequency condition.

In the light of the above statements, choose the correct answer from the options given below:

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Payal Gupta

Contributor-Level 10

$E_{2} > E_{1}$

For statement 1

hf = E₁ - E₂

Since, E₂ > E₁

So, it should be

hf = E₂ – E₁

Therefore statement 1 is wrong

For statement 2

For the jumping of electron from higher energy orbit

(E₂) to lower energy orbit (E₁)

hf = E₂ – E₁

$f = \frac{E_{2} - E_{1}}{h}$

Statement (2) is correct

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