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New answer posted

a year ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

U=ncvT

=2*32*R*300=7479J      

New answer posted

a year ago

0 Follower 3 Views

P
Payal Gupta

Contributor-Level 10

Using newton's law:

2mg – T = 4ma  - (1)

T – mg = ma       - (2)

From (1) & (2) :

m g = 5 m a ⇒ a = g 5 = 2 m / s 2                

T = m g + m g 5 = 6 m g 5                     

New answer posted

a year ago

0 Follower 16 Views

A
alok kumar singh

Contributor-Level 10

Sol. ⇒V?1=2Ucm?-U1?⇒2m/2Vom2+m3-Vo

⇒65Vo-Vo⇒V05

⇒λo=hcm2Voλf=hcM2Vo5

⇒Δλ=8hcmVo

New answer posted

a year ago

0 Follower 7 Views

P
Payal Gupta

Contributor-Level 10

Using conservation of momentum:

60 * v = (60 + 120) * 2

⇒  v = 6m/s

New answer posted

a year ago

0 Follower 7 Views

A
alok kumar singh

Contributor-Level 10

K=QrΔxΔAT

⇒ML2T-2 (L)L2 (θ) (T)⇒M1L1-T-3θ-1

New answer posted

a year ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

L→=r→*mv→

=  (3i^−j^)* (3j^+k^)

=9k^+3 (−j^)−i^

=−i^−3j^+9k^

|L→|==√1+9+81==√91

New answer posted

a year ago

0 Follower 8 Views

P
Payal Gupta

Contributor-Level 10

xR=120?

xL=? L=100*100*10? 310?

xC=1? c=1100*100*10? 6=100?

z=1202+ (100? 10)2=1202+902

= 150 ?

? 32=16075*t? t=32*75160=15

New answer posted

a year ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

eVs=hv-?

 At Vs=0⇒hv=? ⇒? =6.62*10-341014 [5.5]⇒? =6.62*10-341014 [5.5]eV1.6*10-19

=2.27

New answer posted

a year ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

 g=Axx2+a23/2

⇒∫v0?dV=-∫x∞?gdx

⇒O-V=-∫Axa2+x23/2

Let, a2+x2=t2

⇒2xdx=2tdt

⇒xdx=tdt

⇒V=∫Atdtt3⇒-At⇒-Aa2+x2x∞

⇒ V = A a 2 + x 2

New answer posted

a year ago

0 Follower 9 Views

P
Payal Gupta

Contributor-Level 10

From conservation of Energy:

mgl (1−cos60°)=12mv2

⇒v2=2gl (12)=gl

=10*2510=5m/s

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